php.js : is_resource() function

Last update on August 19 2022 21:51:05 (UTC/GMT +8 hours)

is_resource() function

The is_resource () function is used to check whether a variable is a resource or not. The function returns true if the variable is a resource otherwise false.

Version:

1103.1210

Syntax:

is_resource(var_name)

Parameters:

Name	Description	Required / Optional	Type
var_name	The variable being checked	Required	Mixed*

*Mixed : Mixed indicates that a parameter may accept multiple (but not necessarily all) types.

Example of php.js is_resource() function:

In the following web document is_resource() function test whether a variable is resource or not.

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>php.js : is_resource() function example</title>
<script type="text/javascript" src="../../phpjs/variable/variable.min.js"> </script>
</head>
<body>
<h1 style="color: green">php.js : is_resource() function example</h1>
<h3>Return true if variable is a resource.</h3>
<hr />
<script type="text/javascript">
//This is done to make the following JavaScript code compatible to XHTML. <![CDATA[
var_name='A';
if (is_array(var_name))
document.write('The variable is a resource...');
else
document.write('The variable is not resource...');
//]]>
</script>
</body>
</html>

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