C#: Check whether three given numbers are in strict increasing order

Last update on December 20 2024 12:47:42 (UTC/GMT +8 hours)

Strictly Increasing or Equal if Flag True

Write a C# Sharp program to check if three given numbers are in strict increasing order.
For example, 4 7 15, or 45, 56, 67, but not 4 ,5, 8 or 6, 6, 8. However, if a fourth parameter is true, equality is allowed, such as 6, 6, 8 or 7, 7, 7.

Visual Presentation:

Sample Solution:-

C# Sharp Code:

using System;
using System.Linq;

namespace exercises
{
    // Class declaration
    class Program
    {
        // Main method - entry point of the program
        static void Main(string[] args)
        {
            // Calling the 'test' method with different integer values and a boolean flag, and printing the results
            Console.WriteLine(test(1, 2, 3, false));   // Output: True (since flag is false, checks strict ascending order)
            Console.WriteLine(test(1, 2, 3, true));    // Output: True (since flag is true, checks non-strict ascending order)
            Console.WriteLine(test(10, 2, 30, false)); // Output: False (since flag is false, checks strict ascending order)
            Console.WriteLine(test(10, 10, 30, true)); // Output: True (since flag is true, checks non-strict ascending order)
            Console.ReadLine(); // Keeping the console window open
        }

        // Method to check the order of integers based on the flag value
        public static bool test(int x, int y, int z, bool flag)
        {
            // If flag is true, checks for non-strict ascending order (x <= y <= z)
            // If flag is false, checks for strict ascending order (x < y < z)
            return flag ? x <= y && y <= z : x < y && y < z;
        }
    }
}

Sample Output:

True
True
False
True

Flowchart:

C# Sharp Code Editor:

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