C#: Check a given array of integers, length 3 and create a new array

Last update on December 20 2024 12:37:52 (UTC/GMT +8 hours)

Set 7 to 1 if Followed by 5

Write a C# Sharp program to check a given array of integers length 3 and create a array. If there is a 5 in the given array immediately followed by a 7 then set 7 to 1.

Visual Presentation:

Sample Solution:-

C# Sharp Code:

using System; // Importing the System namespace

namespace exercises // Defining a namespace called 'exercises'
{
    class Program // Defining a class named 'Program'
    {
        static void Main(string[] args) // The entry point of the program
        {          
            // Calling the 'test' method with an integer array as an argument and assigning the result to the 'item' array
            int[] item = test(new[] { 1, 5, 7 }); 

            // Outputting text to indicate the start of displaying the new array
            Console.Write("New array: ");

            // Looping through each element of the 'item' array and displaying them
            foreach(var i in item)
            {
                Console.Write(i.ToString()+" "); // Displaying each element of the 'item' array separated by a space
            }               
        }        

        // Method to replace the element following 5 with 1, if 5 is followed by 7 in the input array
        static int[] test(int[] numbers)
        {
            for (var i = 0; i < numbers.Length - 1; i++)
            {
                if (numbers[i].Equals(5) && numbers[i + 1].Equals(7))
                    numbers[i + 1] = 1; // If 5 is followed by 7, replace the following element with 1
            }
            return numbers; // Returning the modified array
        } 
    }
}

Sample Output:

New array: 1 5 1

Flowchart:

C# Sharp Code Editor:

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