C Exercises: Return the counting sort on an array
C Array: Exercise-59 with Solution
Write a program in C to return the counting sort on an array.
Expected Output :
The given array is : 4 14 8 0 2 5 2 1 0 17 9 0 5
After sorting the elements in the array are: 0 0 0 1 2 2 4 5 5 8 9 14 17
To perform counting sort on an array, the program first determines the range of the input values. It then creates a count array to store the frequency of each element. By accumulating the counts and then using them to place elements in their correct positions, the program efficiently sorts the array. This algorithm is particularly effective for arrays with a limited range of integer values.
Sample Solution:
C Code:
#include <stdio.h>
// Function to perform counting sort on the array
void counting_sort(int arr1[], int n, int max) {
int count[50] = {0}; // Initializing an array to store count of elements
int i, j;
// Counting occurrences of each element in the array
for (i = 0; i < n; ++i)
count[arr1[i]] = count[arr1[i]] + 1;
printf("After sorting the elements in the array are: ");
// Reconstructing the sorted array using count array
for (i = 0; i <= max; ++i) {
for (j = 1; j <= count[i]; ++j) {
printf("%d ", i); // Printing the element based on its count
}
}
}
int main() {
int max = 0; // Initializing max value
int arr1[] = {4, 14, 8, 0, 2, 5, 2, 1, 0, 17, 9, 0, 5};
int n = sizeof(arr1) / sizeof(arr1[0]);
int i;
//------------- print original array ------------------
printf("The given array is : ");
for (i = 0; i < n; i++) {
if (arr1[i] > max)
max = arr1[i]; // Finding maximum element in the array
printf("%d ", arr1[i]);
}
printf("\n");
//------------------------------------------------------
counting_sort(arr1, n, max); // Function call for counting sort
return 0;
}
Output:
The given array is : 4 14 8 0 2 5 2 1 0 17 9 0 5 After sorting the elements in the array are: 0 0 0 1 2 2 4 5 5 8 9 14 17
Flowchart:
C Programming Code Editor:
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