C Exercises: Move all zeroes to the end of a given array
C Array: Exercise-58 with Solution
Write a program in C to move all zeroes to the end of a given array.
Expected Output :
The given array is : 2 5 7 0 4 0 7 -5 8 0
The new array is:
2 5 7 8 4 -5 7 0 0 0
To move all zeroes to the end of a given array, the program iterates through the array while maintaining a position pointer for non-zero elements. As it encounters non-zero elements, it places them at the current position pointer and increments the pointer. After processing all elements, the remaining positions in the array are filled with zeroes. This approach maintains the relative order of the non-zero elements.
Visual Presentation:
Sample Solution:
C Code:
#include <stdio.h>
// Function to segregate zeros in an array to the right side
void PickOutZeros(int *arr1, int arr_size) {
int tmp, lft = 0, rgt = arr_size - 1;
// Loop until the pointers meet or cross each other
while (rgt > lft) {
// Move the left pointer until a non-zero element is found
while (arr1[lft] != 0)
lft++;
// Move the right pointer until a non-zero element is found
while (arr1[rgt] == 0)
rgt--;
// Swap the non-zero elements at the left and right pointers if left is less than right
if (lft < rgt) {
tmp = arr1[lft];
arr1[lft] = arr1[rgt];
arr1[rgt] = tmp;
}
}
}
int main() {
int arr1[] = {2, 5, 7, 0, 4, 0, 7, -5, 8, 0};
int n = sizeof(arr1) / sizeof(arr1[0]);
int i;
//------------- print original array ------------------
printf("The given array is: ");
for (i = 0; i < n; i++) {
printf("%d ", arr1[i]);
}
printf("\n");
//------------------------------------------------------
// Function call to segregate zeros to the right side
PickOutZeros(arr1, n);
// Printing the new array after segregating zeros
printf("The new array is: \n");
for (i = 0; i < n; i++) {
printf("%d ", arr1[i]);
}
return 0;
}
Sample Output:
The given array is : 2 5 7 0 4 0 7 -5 8 0 The new array is: 2 5 7 8 4 -5 7 0 0 0
Flowchart:
C Programming Code Editor:
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