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SQLite Exercise: Display the names using alias name "First Name", "Last Name"

Write a query to display the names (first_name, last_name) using alias name "First Name", "Last Name".

Sample table : employees

+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
| EMPLOYEE_ID | FIRST_NAME  | LAST_NAME   | EMAIL    | PHONE_NUMBER       | HIRE_DATE  | JOB_ID     | SALARY   | COMMISSION_PCT | MANAGER_ID | DEPARTMENT_ID |
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
|         100 | Steven      | King        | SKING    | 515.123.4567       | 1987-06-17 | AD_PRES    | 24000.00 |           0.00 |          0 | 		  90 |
|         101 | Neena       | Kochhar     | NKOCHHAR | 515.123.4568       | 1987-06-18 | AD_VP      | 17000.00 |           0.00 |        100 |            90 |
|         102 | Lex         | De Haan     | LDEHAAN  | 515.123.4569       | 1987-06-19 | AD_VP      | 17000.00 |           0.00 |        100 |            90 |
|         103 | Alexander   | Hunold      | AHUNOLD  | 590.423.4567       | 1987-06-20 | IT_PROG    |  9000.00 |           0.00 |        102 |            60 |
|         104 | Bruce       | Ernst       | BERNST   | 590.423.4568       | 1987-06-21 | IT_PROG    |  6000.00 |           0.00 |        103 |            60 |
|         105 | David       | Austin      | DAUSTIN  | 590.423.4569       | 1987-06-22 | IT_PROG    |  4800.00 |           0.00 |        103 |            60 |
|         106 | Valli       | Pataballa   | VPATABAL | 590.423.4560       | 1987-06-23 | IT_PROG    |  4800.00 |           0.00 |        103 |            60 |
|         107 | Diana       | Lorentz     | DLORENTZ | 590.423.5567       | 1987-06-24 | IT_PROG    |  4200.00 |           0.00 |        103 |            60 |
|         108 | Nancy       | Greenberg   | NGREENBE | 515.124.4569       | 1987-06-25 | FI_MGR     | 12000.00 |           0.00 |        101 |           100 |
|         109 | Daniel      | Faviet      | DFAVIET  | 515.124.4169       | 1987-06-26 | FI_ACCOUNT |  9000.00 |           0.00 |        108 |           100 |
........
|         206 | William     | Gietz       | WGIETZ   | 515.123.8181       | 1987-10-01 | AC_ACCOUNT |  8300.00 |           0.00 |        205 |           110 |
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+

View the table

SQLite Code :

-- Selecting the "first_name" column and renaming it as "First Name"
-- Selecting the "last_name" column and renaming it as "Last Name"
SELECT first_name "First Name", last_name "Last Name"
-- Specifying the table from which to retrieve the data, in this case, "employees"
FROM employees;

Output:

First Name  Last Name
----------  ----------
Steven      King
Neena       Kochhar
Lex         De Haan
Alexander   Hunold
Bruce       Ernst
...			...
Pat         Fay
Susan       Mavris
Hermann     Baer
Shelley     Higgins
William     Gietz

Explanation:

The above SQLite query retrieves data from a table named "employees." It selects the "first_name" column from the table and renames it as "First Name." Similarly, it selects the "last_name" column and renames it as "Last Name." The result is a list of employee first names and last names from the "employees" table.

Go to:


PREV : Basic SELECT statement
NEXT : Write a query to get unique department ID from employee table.

Practice SQLite Online


Model Database

Employee Model  Database - w3resource online SQLite practice

Structure of 'hr' database :

hr database

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