SQL Exercises: The customer whose ID is 2001 is below Mc Lyons
SQL SUBQUERY: Exercise-7 with Solution
7. Write a query to display all the customers whose ID is 2001 below the salesperson ID of Mc Lyon.
Sample table: Salesmansalesman_id name city commission ----------- ---------- ---------- ---------- 5001 James Hoog New York 0.15 5002 Nail Knite Paris 0.13 5005 Pit Alex London 0.11 5006 Mc Lyon Paris 0.14 5003 Lauson Hen San Jose 0.12 5007 Paul Adam Rome 0.13Sample table : Customer
customer_id cust_name city grade salesman_id ----------- ------------ ---------- ---------- ----------- 3002 Nick Rimando New York 100 5001 3005 Graham Zusi California 200 5002 3001 Brad Guzan London 100 5005 3004 Fabian Johns Paris 300 5006 3007 Brad Davis New York 200 5001 3009 Geoff Camero Berlin 100 5003 3008 Julian Green London 300 5002 3003 Jozy Altidor Moncow 200 5007
Sample Solution:
-- Selecting all columns from the 'customer' table
SELECT *
-- Specifying the table to retrieve data from ('customer')
FROM customer
-- Filtering the results based on the condition that 'customer_id' is equal to the result of a subquery
WHERE customer_id =
-- Subquery: Selecting 'salesman_id - 2001' from the 'salesman' table where 'name' is 'Mc Lyon'
(SELECT salesman_id - 2001
FROM salesman
WHERE name = 'Mc Lyon');
Output of the Query:
customer_id cust_name city grade salesman_id 3005 Graham Zusi California 200 5002
Explanation:
The said SQL query selects all columns (*) from the customer table where the 'customer_id' is equal to the 'salesman_id' minus 2001 from the salesman table where the 'name' is equal to 'Mc Lyon'. In other words, it is selecting the customer with the ID that is the salesman_id of the salesman 'Mc Lyon' -2001.
Visual Explanation:
Practice Online
Sample Database: inventory
Query Visualization:
Duration:
Rows:
Cost:
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