SQL Exercises: Different grades than other Dallas customers
SQL SUBQUERY : Exercise-30 with Solution
30. From the following tables write a SQL query to find all those customers who have different grades than any customer who lives in Dallas City. Return customer_id, cust_name,city, grade and salesman_id.
Sample table : Customercustomer_id cust_name city grade salesman_id ----------- ------------ ---------- ---------- ----------- 3002 Nick Rimando New York 100 5001 3005 Graham Zusi California 200 5002 3001 Brad Guzan London 100 5005 3004 Fabian Johns Paris 300 5006 3007 Brad Davis New York 200 5001 3009 Geoff Camero Berlin 100 5003 3008 Julian Green London 300 5002 3003 Jozy Altidor Moncow 200 5007
Sample Solution:
-- Selecting all columns from the 'customer' table
SELECT *
-- Specifying the table to retrieve data from ('customer')
FROM customer
-- Filtering the results based on the condition that 'grade' is not equal to any value in the set of 'grade' values returned by a subquery
WHERE NOT grade = ANY
-- Subquery: Selecting 'grade' values from the 'customer' table where 'city' is 'Dallas'
(SELECT grade
FROM customer
WHERE city='Dallas');
Output of the Query:
customer_id cust_name city grade salesman_id 3002 Nick Rimando New York 100 5001 3007 Brad Davis New York 200 5001 3005 Graham Zusi California 200 5002 3008 Julian Green London 300 5002 3004 Fabian Johnson Paris 300 5006 3009 Geoff Cameron Berlin 100 5003 3003 Jozy Altidor Moscow 200 5007 3001 Brad Guzan London 5005
Explanation:
The above SQL query is selecting all columns and rows from the 'customer' table where the grade is not equal to any of the grades found in the subquery. The subquery is selecting the grade from the 'customer' table where the city is equal to 'Dallas'. So the main query is getting the rows of all customers whose grade is not equal to any grade of customers living in Dallas.
Visual Explanation:
Practice Online
Sample Database: inventory
Query Visualization:
Duration:
Rows:
Cost:
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