SQL Exercises: Orders of the salesman working for the customer 3007
3. From the following tables write a SQL query to find all orders generated by the salespeople who may work for customers whose id is 3007. Return ord_no, purch_amt, ord_date, customer_id, salesman_id.
Sample table: Ordersord_no purch_amt ord_date customer_id salesman_id ---------- ---------- ---------- ----------- ----------- 70001 150.5 2012-10-05 3005 5002 70009 270.65 2012-09-10 3001 5005 70002 65.26 2012-10-05 3002 5001 70004 110.5 2012-08-17 3009 5003 70007 948.5 2012-09-10 3005 5002 70005 2400.6 2012-07-27 3007 5001 70008 5760 2012-09-10 3002 5001 70010 1983.43 2012-10-10 3004 5006 70003 2480.4 2012-10-10 3009 5003 70012 250.45 2012-06-27 3008 5002 70011 75.29 2012-08-17 3003 5007 70013 3045.6 2012-04-25 3002 5001
Sample Solution:
-- Selecting all columns from the 'orders' table
SELECT *
-- Specifying the table to retrieve data from ('orders')
FROM orders
-- Filtering the results based on the condition that 'salesman_id' is equal to the result of a subquery
WHERE salesman_id =
-- Subquery: Selecting distinct 'salesman_id' from the 'orders' table where 'customer_id' is 3007
(SELECT DISTINCT salesman_id
FROM orders
WHERE customer_id = 3007);
Output of the Query:
ord_no purch_amt ord_date customer_id salesman_id 70002 65.26 2012-10-05 3002 5001 70005 2400.60 2012-07-27 3007 5001 70008 5760.00 2012-09-10 3002 5001 70013 3045.60 2012-04-25 3002 5001
Explanation:
The said SQL query selects all columns (*) from the orders table where the 'salesman_id' is equal to the distinct 'salesman_id' from the orders table where the 'customer_id' is equal to 3007. In other words, it is selecting all rows from the orders table where the salesman who serviced a customer with the ID of 3007, also serviced.
Visual Explanation:
Practice Online
Sample Database: inventory
Query Visualization:
Duration:
Rows:
Cost:
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Previous SQL Exercise: Show all the orders for the London-based salesman.
Next SQL Exercise: Orders with values greater than the given date average.
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