SQL Exercises: Using between operator to get a value from a range
SQL Wildcard & Special Operator: Exercise-5 with Solution
From the following table, write a SQL query to find salespeople who receive commissions between 0.12 and 0.14 (begin and end values are included). Return salesman_id, name, city, and commission.
Sample table: salesman
salesman_id | name | city | commission -------------+------------+----------+------------ 5001 | James Hoog | New York | 0.15 5002 | Nail Knite | Paris | 0.13 5005 | Pit Alex | London | 0.11 5006 | Mc Lyon | Paris | 0.14 5007 | Paul Adam | Rome | 0.13 5003 | Lauson Hen | San Jose | 0.12
Sample Solution:
-- Selecting all columns from the 'salesman' table
SELECT *
-- Specifying the table to retrieve data from ('salesman')
FROM salesman
-- Filtering the results based on the condition that 'commission' is between 0.12 and 0.14
WHERE commission BETWEEN 0.12 AND 0.14;
Output of the Query:
salesman_id name city commission 5002 Nail Knite Paris 0.13 5006 Mc Lyon Paris 0.14 5007 Paul Adam Rome 0.13 5003 Lauson Hen San Jose0.12
Code Explanation:
The said SQL query that selects all columns (*) from a table called 'salesman' where the "commission" is between 0.12 and 0.14. It will return all the rows in the 'salesman' table where the "commission" is greater than or equal to 0.12 and less than or equal to 0.14.
Relational Algebra Expression:
Relational Algebra Tree:
Explanation:
Visual presentation :
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