SQL Exercises: Sort records using in operator
From the following table, write a SQL query to retrieve the details of all customers whose ID belongs to any of the values 3007, 3008 or 3009. Return customer_id, cust_name, city, grade, and salesman_id.
Sample table: customer
customer_id | cust_name | city | grade | salesman_id -------------+----------------+------------+-------+------------- 3002 | Nick Rimando | New York | 100 | 5001 3007 | Brad Davis | New York | 200 | 5001 3005 | Graham Zusi | California | 200 | 5002 3008 | Julian Green | London | 300 | 5002 3004 | Fabian Johnson | Paris | 300 | 5006 3009 | Geoff Cameron | Berlin | 100 | 5003 3003 | Jozy Altidor | Moscow | 200 | 5007 3001 | Brad Guzan | London | | 5005
Sample Solution:
-- This query selects all columns from the 'customer' table.
SELECT *
-- Specifies the table from which to retrieve the data (in this case, 'customer').
FROM customer
-- Filters the rows to only include those where the 'customer_id' column has one of the values 3007, 3008, or 3009.
WHERE customer_id IN (3007, 3008, 3009);
Output of the Query:
customer_id cust_name city grade salesman_id 3007 Brad Davis New York 200 5001 3008 Julian Green London 300 5002 3009 Geoff Cameron Berlin 100 5003
Code Explanation:
The said query in SQL that selects all columns (*) from a table called 'customer' where the "customer_id" is in the list of values (3007, 3008, 3009).
It will return a list of all the rows in the 'customer' table in which the 'customer_id' matches any of the specified values in the query.
Relational Algebra Expression:
Relational Algebra Tree:
Explanation:
Visual presentation:
Query Visualization:
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Previous SQL Exercise: Filter records using not in operator.
Next SQL Exercise: Using between operator to get a value from a range.
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