SQL Exercise: Employee and sanction amount for their department
SQL JOINS: Exercise-27 with Solution
From the following tables write a SQL query to display the first and last names of each employee, as well as the department name and sanction amount.
Sample table: emp_department
DPT_CODE DPT_NAME DPT_ALLOTMENT -------- --------------- ------------- 57 IT 65000 63 Finance 15000 47 HR 240000 27 RD 55000 89 QC 75000
Sample table: emp_details
EMP_IDNO EMP_FNAME EMP_LNAME EMP_DEPT --------- --------------- --------------- ---------- 127323 Michale Robbin 57 526689 Carlos Snares 63 843795 Enric Dosio 57 328717 Jhon Snares 63 444527 Joseph Dosni 47 659831 Zanifer Emily 47 847674 Kuleswar Sitaraman 57 748681 Henrey Gabriel 47 555935 Alex Manuel 57 539569 George Mardy 27 733843 Mario Saule 63 631548 Alan Snappy 27 839139 Maria Foster 57
Sample Solution:
-- Selecting specific columns and renaming them for clarity
SELECT emp_details.emp_fname AS "First Name", emp_lname AS "Last Name",
emp_department.dpt_name AS "Department",
dpt_allotment AS "Amount Allotted"
-- Specifying the tables to retrieve data from ('emp_details' and 'emp_department')
FROM emp_details
-- Performing an inner join based on the equality of 'emp_dept' in 'emp_details' and 'dpt_code' in 'emp_department'
INNER JOIN emp_department
ON emp_details.emp_dept = emp_department.dpt_code;
Output of the Query:
First Name Last Name Department Amount Allotted Alan Snappy RD 55000 Maria Foster IT 65000 Michale Robbin IT 65000 Carlos Snares Finance 15000 Enric Dosio IT 65000 Jhon Snares Finance 15000 Joseph Dosni HR 240000 Zanifer Emily HR 240000 Kuleswar Sitaraman IT 65000 Henrey Gabriel HR 240000 Alex Manuel IT 65000 George Mardy RD 55000 Mario Saule Finance 15000
Explanation:
The said SQL query is selecting the employee's first name (emp_details.emp_fname) with an alias 'First Name', last name (emp_lname) with an alias 'Last Name', department name (emp_department.dpt_name) with an alias 'Department', and department allotment (dpt_allotment) with an alias 'Amount Allotted' by joining the emp_details table and emp_department table on the emp_dept column of the emp_details table and the dpt_code column of the emp_department table. The query is joining the two tables together and displaying the selected columns from both tables.
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Previous SQL Exercise: Display employees including their department.
Next SQL Exercise: Find employees and departments with a given budget.
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