SQL Exercise: Purchase amount and commission for the last order

Last update on March 08 2025 08:18:11 (UTC/GMT +8 hours)

Daily Totals with Commission Calculation

From the following table, write a SQL query to calculate the summation of purchase amount, total commission (15% for all salespeople) by each order date. Sort the result-set on order date. Return order date, summation of purchase amount and commission.

Sample table: orders

ord_no      purch_amt   ord_date    customer_id  salesman_id
----------  ----------  ----------  -----------  -----------
70001       150.5       2012-10-05  3005         5002
70009       270.65      2012-09-10  3001         5005
70002       65.26       2012-10-05  3002         5001
70004       110.5       2012-08-17  3009         5003
70007       948.5       2012-09-10  3005         5002
70005       2400.6      2012-07-27  3007         5001
70008       5760        2012-09-10  3002         5001
70010       1983.43     2012-10-10  3004         5006
70003       2480.4      2012-10-10  3009         5003
70012       250.45      2012-06-27  3008         5002
70011       75.29       2012-08-17  3003         5007
70013       3045.6      2012-04-25  3002         5001

Sample Solution:

-- This query selects specific columns ('ord_date', the sum of 'purch_amt', and the calculated value of 15% of the sum of 'purch_amt') from the 'orders' table.
-- It groups the result set by 'ord_date', sums the 'purch_amt' for each group, and calculates 15% of the sum of 'purch_amt'.
-- Finally, it orders the result set by 'ord_date' in ascending order.
SELECT ord_date, SUM(purch_amt), SUM(purch_amt) * 0.15
-- Specifies the table from which to retrieve the data (in this case, 'orders').
FROM orders
-- Groups the result set by 'ord_date', summing the 'purch_amt' for each group.
GROUP BY ord_date
-- Orders the result set by 'ord_date' in ascending order.
ORDER BY ord_date;

Output of the Query:

ord_date	sum		?column?
2012-04-25	3045.60		456.8400
2012-06-27	250.45		37.5675
2012-07-27	2400.60		360.0900
2012-08-17	185.79		27.8685
2012-09-10	6979.15		1046.8725
2012-10-05	215.76		32.3640
2012-10-10	4463.83		669.5745

Code Explanation:

The said query in SQL that retrieves the order date, sum of purchase amounts, and sum of purchase amounts multiplied by 0.15 (15%) from the 'orders' table. The result set is grouped by the "ord_date" column and ordered by the "ord_date" in ascending order.
This query returns a total purchase amount as well as a calculated column that shows 15% of the total purchase amount, organized according to when the order was placed.

Explanation :

Visual presentation :

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Query Visualization:

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For more Practice: Solve these Related Problems:

• Write a SQL query to group orders by ord_date, summing purch_amt and calculating total commission as 15% of the sum, then order the results by ord_date ascending.
• Write a SQL query to retrieve ord_date, total purchase amount, and computed commission (15% of the total) for each day, filtering out dates where the sum is below 100.
• Write a SQL query to select ord_date, the sum of purch_amt, and total commission (sum(purch_amt)*0.15) for each day, including only dates with at least two orders.
• Write a SQL query to calculate daily totals for purch_amt and commission (15% of total), and add a computed column showing the difference between total purchase and commission, sorting by ord_date.
• Write a SQL query to output ord_date, summation of purch_amt, and commission (15% of the summation) for each order date, filtering out records where the commission is not a whole number.

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