SQL Exercises: Count all orders for a specific date
18. Count Orders on '2012-08-17'
From the following table, write a SQL query to count all the orders generated on '2012-08-17'. Return number of orders.
Sample table: orders
ord_no purch_amt ord_date customer_id salesman_id ---------- ---------- ---------- ----------- ----------- 70001 150.5 2012-10-05 3005 5002 70009 270.65 2012-09-10 3001 5005 70002 65.26 2012-10-05 3002 5001 70004 110.5 2012-08-17 3009 5003 70007 948.5 2012-09-10 3005 5002 70005 2400.6 2012-07-27 3007 5001 70008 5760 2012-09-10 3002 5001 70010 1983.43 2012-10-10 3004 5006 70003 2480.4 2012-10-10 3009 5003 70012 250.45 2012-06-27 3008 5002 70011 75.29 2012-08-17 3003 5007 70013 3045.6 2012-04-25 3002 5001
Sample Solution:
-- This query counts the number of rows in the 'orders' table where the 'ord_date' is '2012-08-17'.
SELECT COUNT(*)
-- Specifies the table from which to retrieve the data (in this case, 'orders').
FROM orders
-- Filters the rows to only include those where the 'ord_date' is '2012-08-17'.
WHERE ord_date = '2012-08-17';
Output of the Query:
count 2
Code Explanation:
The said SQL query retrieves the count of rows from the 'orders' table where the ord_date is equal to '2012-08-17'. The result will be a single row with a single column indicating the number of orders placed on '2012-08-17'.
Relational Algebra Expression:
Relational Algebra Tree:
Explanation:

Visual presentation:

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Practice Online
For more Practice: Solve these Related Problems:
- Write a SQL query to count the number of orders placed on '2012-09-10'.
- Write a SQL query to count the number of orders placed on '2012-10-05', but only for orders with a purchase amount greater than 500.
- Write a SQL query to count the number of orders placed on '2012-08-17', but only for orders placed by customer ID 3009.
- Write a SQL query to count the number of orders placed on '2012-07-27', but only for orders placed by salesman ID 5001.
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