SQL Exercises: Count all orders for a specific date
SQL Aggregate Functions: Exercise-18 with Solution
From the following table, write a SQL query to count all the orders generated on '2012-08-17'. Return number of orders.
Sample table: orders
Sample Solution:
SELECT COUNT(*)
FROM orders
WHERE ord_date='2012-08-17';
Output of the Query:
count 2
Code Explanation:
The said SQL query retrieves the count of rows from the 'orders' table where the ord_date is equal to '2012-08-17'. The result will be a single row with a single column indicating the number of orders placed on '2012-08-17'.
Relational Algebra Expression:
Relational Algebra Tree:
Explanation:

Visual presentation:

Practice Online
Query Visualization:
Duration:

Rows:

Cost:

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Previous SQL Exercise: Customer with the highest purchase amount.
Next SQL Exercise: Number of non NULL city values for salesmen.
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SQL: Tips of the Day
What is the best way to paginate results in SQL Server?
SELECT * FROM ( SELECT ROW_NUMBER() OVER ( ORDER BY OrderDate ) AS RowNum, * FROM Orders WHERE OrderDate >= '1980-01-01' ) AS RowConstrainedResult WHERE RowNum >= 1 AND RowNum < 20 ORDER BY RowNum
Database: SQL Server
Ref: https://bit.ly/3MGrNlk
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