﻿ SQL: Count all orders for a specific date

# SQL Exercises: Count all orders for a specific date

## SQL Aggregate Functions: Exercise-18 with Solution

From the following table, write a SQL query to count all the orders generated on '2012-08-17'. Return number of orders.

Sample table: orders

Sample Solution:

``````SELECT COUNT(*)
FROM orders
WHERE ord_date='2012-08-17';
``````

Output of the Query:

```count
2
```

Code Explanation:

The said SQL query retrieves the count of rows from the 'orders' table where the ord_date is equal to '2012-08-17'. The result will be a single row with a single column indicating the number of orders placed on '2012-08-17'.

Relational Algebra Expression:

Relational Algebra Tree:

Explanation:

Visual presentation:

## Query Visualization:

Duration:

Rows:

Cost:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous SQL Exercise: Customer with the highest purchase amount.
Next SQL Exercise: Number of non NULL city values for salesmen.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

﻿

## SQL: Tips of the Day

What is the best way to paginate results in SQL Server?

```SELECT  *
FROM    ( SELECT    ROW_NUMBER() OVER ( ORDER BY OrderDate ) AS RowNum, *
FROM      Orders
WHERE     OrderDate >= '1980-01-01'
) AS RowConstrainedResult
WHERE   RowNum >= 1
AND RowNum < 20
ORDER BY RowNum
```

Database: SQL Server

Ref: https://bit.ly/3MGrNlk

We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook