SQL Exercises: Highest purchase amount from customers
SQL Aggregate Functions: Exercise-15 with Solution
From the following table, write a SQL query to determine the maximum order amount for each customer. The customer ID should be in the range 3002 and 3007(Begin and end values are included.). Return customer id and maximum purchase amount.
Sample table: orders
ord_no purch_amt ord_date customer_id salesman_id ---------- ---------- ---------- ----------- ----------- 70001 150.5 2012-10-05 3005 5002 70009 270.65 2012-09-10 3001 5005 70002 65.26 2012-10-05 3002 5001 70004 110.5 2012-08-17 3009 5003 70007 948.5 2012-09-10 3005 5002 70005 2400.6 2012-07-27 3007 5001 70008 5760 2012-09-10 3002 5001 70010 1983.43 2012-10-10 3004 5006 70003 2480.4 2012-10-10 3009 5003 70012 250.45 2012-06-27 3008 5002 70011 75.29 2012-08-17 3003 5007 70013 3045.6 2012-04-25 3002 5001
Sample Solution:
-- This query retrieves the maximum 'purch_amt' value for each 'customer_id' from the 'orders' table.
-- It only includes rows where the 'customer_id' is between 3002 and 3007.
SELECT customer_id, MAX(purch_amt)
-- Specifies the table from which to retrieve the data (in this case, 'orders').
FROM orders
-- Filters the rows to only include those where the 'customer_id' is between 3002 and 3007.
WHERE customer_id BETWEEN 3002 AND 3007
-- Groups the result set by the 'customer_id' column.
GROUP BY customer_id;
Output of the Query:
customer_id max 3002 5760.00 3007 2400.60 3004 1983.43 3003 75.29 3005 948.50
Code Explanation:
The said SQL query retrieves the customer_id and maximum purchase amount (purch_amt) for customers with id between 3002 and 3007 from the 'orders' table. The result will show the maximum purchase amount made by each customer in the specified range, with the customer_id being grouped together.
Relational Algebra Expression:
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Explanation :
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Previous SQL Exercise: Higher purchase amount by the customer within a list.
Next SQL Exercise: Customer details and purchases over a certain amount.
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