﻿ SQL: Highest purchase amount of customers on a given date

# SQL Exercises: Highest purchase amount of customers on a given date

## SQL Aggregate Functions: Exercise-12 with Solution

From the following table, write a SQL query to find the highest order (purchase) amount by each customer on a particular order date. Filter the result by highest order (purchase) amount above 2000.00. Return customer id, order date and maximum purchase amount.

Sample table: orders

Sample Solution:

``````SELECT customer_id,ord_date,MAX(purch_amt)
FROM orders
GROUP BY customer_id,ord_date
HAVING MAX(purch_amt)>2000.00;
``````

Output of the Query:

```customer_id	ord_date	max
3007		2012-07-27	2400.60
3002		2012-09-10	5760.00
3009		2012-10-10	2480.40
3002		2012-04-25	3045.60
```

Code Explanation:

The said SQL query retrieves the customer id, order date, and the maximum purchase amount for each combination of customer id and order date in the 'orders' table.
The result will be grouped by customer id and order date, and only those groups with a maximum purchase amount greater than 2000.00 will be returned. The "HAVING" clause is used to specify the condition for the groups to be returned.

Relational Algebra Expression:

Relational Algebra Tree:

Explanation:

Visual presentation:

## Query Visualization:

Duration:

Rows:

Cost:

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Previous SQL Exercise: Highest purchase amount on a date for each salesman.
Next SQL Exercise: Higher purchase amount of customers within a range.

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## SQL: Tips of the Day

What is the best way to paginate results in SQL Server?

```SELECT  *
FROM    ( SELECT    ROW_NUMBER() OVER ( ORDER BY OrderDate ) AS RowNum, *
FROM      Orders
WHERE     OrderDate >= '1980-01-01'
) AS RowConstrainedResult
WHERE   RowNum >= 1
AND RowNum < 20
ORDER BY RowNum
```

Database: SQL Server

Ref: https://bit.ly/3MGrNlk

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