SQL Exercises: Find the highest purchase amount each customer ordered
SQL Aggregate Functions: Exercise-10 with Solution
From the following table, write a SQL query to find the highest purchase amount ordered by each customer on a particular date. Return, order date and highest purchase amount.
Sample table: orders
ord_no purch_amt ord_date customer_id salesman_id ---------- ---------- ---------- ----------- ----------- 70001 150.5 2012-10-05 3005 5002 70009 270.65 2012-09-10 3001 5005 70002 65.26 2012-10-05 3002 5001 70004 110.5 2012-08-17 3009 5003 70007 948.5 2012-09-10 3005 5002 70005 2400.6 2012-07-27 3007 5001 70008 5760 2012-09-10 3002 5001 70010 1983.43 2012-10-10 3004 5006 70003 2480.4 2012-10-10 3009 5003 70012 250.45 2012-06-27 3008 5002 70011 75.29 2012-08-17 3003 5007 70013 3045.6 2012-04-25 3002 5001
Sample Solution:
-- This query retrieves the maximum 'purch_amt' value for each combination of 'customer_id' and 'ord_date' from the 'orders' table.
SELECT customer_id, ord_date, MAX(purch_amt)
-- Specifies the table from which to retrieve the data (in this case, 'orders').
FROM orders
-- Groups the result set by the 'customer_id' and 'ord_date' columns.
GROUP BY customer_id, ord_date;
Output of the Query:
customer_id ord_date max 3002 2012-10-05 65.26 3003 2012-08-17 75.29 3005 2012-10-05 150.50 3007 2012-07-27 2400.60 3009 2012-08-17 110.50 3001 2012-09-10 270.65 3002 2012-09-10 5760.00 3005 2012-09-10 948.50 3009 2012-10-10 2480.40 3008 2012-06-27 250.45 3004 2012-10-10 1983.43 3002 2012-04-25 3045.60
Code Explanation:
The said SQL query retrieves the customer id, order date, and the maximum purchase amount for each combination of customer id and order date in the 'orders' table. The result will be grouped by customer id and order date.
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