SQL Exercise: Employees who does not earn any commission

Last update on March 31 2023 06:07:56 (UTC/GMT +8 hours)

SQL SORTING and FILTERING on HR Database: Exercise-8 with Solution

8. From the following table, write a SQL query to find those employees who do not earn any commission. Return full name (first and last name), and salary.

Sample table : employees

Sample Solution:

SELECT first_name ||' '||last_name AS Full_Name, salary
 FROM  employees
  WHERE commission_pct IS NULL;

Sample Output:

 full_name | salary
-----------+--------
(0 rows)

Code Explanation:

The said query in SQL that retrieves the first name, last name concatenated as "Full_Name" and salary columns from the 'employees' table where the commission_pct is null.

Practice Online

N.B.: In certain instances not null is removed in table structure, so results may vary.

Query Visualization:

Duration:

Rows:

Cost:

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Previous SQL Exercise: Employees with salaries of given range and commission.
Next SQL Exercise: Find employees whose salary is within 9000 to 17000.

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SQL: Tips of the Day

Difference between natural join and inner join

One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned-

Consider:

TableA                           TableB
+------------+----------+        +--------------------+    
|Column1     | Column2  |        |Column1  |  Column3 |
+-----------------------+        +--------------------+
| 1          |  2       |        | 1       |   3      |
+------------+----------+        +---------+----------+

The INNER JOIN of TableA and TableB on Column1 will return

SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1);
SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;

+------------+-----------+---------------------+    
| a.Column1  | a.Column2 | b.Column1| b.Column3|
+------------------------+---------------------+
| 1          |  2        | 1        |   3      |
+------------+-----------+----------+----------+

The NATURAL JOIN of TableA and TableB on Column1 will return:

SELECT * FROM TableA NATURAL JOIN TableB
+------------+----------+----------+    
|Column1     | Column2  | Column3  |
+-----------------------+----------+
| 1          |  2       |   3      |
+------------+----------+----------+

Ref: https://bit.ly/3AG5CId

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