w3resource

SQL Exercise: Employees with salaries of given range and commission

SQL SORTING and FILTERING on HR Database: Exercise-7 with Solution

7. From the following table, write a SQL query to find those employees who earn between 8000 and 12000 (Begin and end values are included.) and get some commission. These employees joined before ‘1987-06-05’ and were not included in the department numbers 40, 120 and 70. Return all fields.

Sample table employees


Sample Solution: 

SELECT *
 FROM employees
  WHERE salary BETWEEN 8000 AND 12000 
      AND commission_pct IS NOT NULL
       OR  department_id NOT IN (40 , 120 , 70)
          AND   hire_date < '2003-06-05'

Sample Output:

employee_id|first_name |last_name |email   |phone_number      |hire_date |job_id    |salary  |commission_pct|manager_id|department_id|
-----------|-----------|----------|--------|------------------|----------|----------|--------|--------------|----------|-------------|
        102|Lex        |De Haan   |LDEHAAN |515.123.4569      |2001-01-13|AD_VP     |17000.00|          0.00|       100|           90|
        103|Alexander  |Hunold    |AHUNOLD |590.423.4567      |2006-01-03|IT_PROG   | 9000.00|          0.00|       102|           60|
        108|Nancy      |Greenberg |NGREENBE|515.124.4569      |2002-08-17|FI_MGR    |12000.00|          0.00|       101|          100|
        109|Daniel     |Faviet    |DFAVIET |515.124.4169      |2002-08-16|FI_ACCOUNT| 9000.00|          0.00|       108|          100|
        110|John       |Chen      |JCHEN   |515.124.4269      |2005-09-28|FI_ACCOUNT| 8200.00|          0.00|       108|          100|
        114|Den        |Raphaely  |DRAPHEAL|515.127.4561      |2002-12-07|PU_MAN    |11000.00|          0.00|       100|           30|
        115|Alexander  |Khoo      |AKHOO   |515.127.4562      |2003-05-18|PU_CLERK  | 3100.00|          0.00|       114|           30|
        120|Matthew    |Weiss     |MWEISS  |650.123.1234      |2004-07-18|ST_MAN    | 8000.00|          0.00|       100|           50|
        121|Adam       |Fripp     |AFRIPP  |650.123.2234      |2005-04-10|ST_MAN    | 8200.00|          0.00|       100|           50|
        122|Payam      |Kaufling  |PKAUFLIN|650.123.3234      |2003-05-01|ST_MAN    | 7900.00|          0.00|       100|           50|
        147|Alberto    |Errazuriz |AERRAZUR|011.44.1344.429278|2005-03-10|SA_MAN    |12000.00|          0.30|       100|           80|
        148|Gerald     |Cambrault |GCAMBRAU|011.44.1344.619268|2007-10-15|SA_MAN    |11000.00|          0.30|       100|           80|
        149|Eleni      |Zlotkey   |EZLOTKEY|011.44.1344.429018|2008-01-29|SA_MAN    |10500.00|          0.20|       100|           80|
        150|Peter      |Tucker    |PTUCKER |011.44.1344.129268|2005-01-30|SA_REP    |10000.00|          0.30|       145|           80|
        151|David      |Bernstein |DBERNSTE|011.44.1344.345268|2005-03-24|SA_REP    | 9500.00|          0.25|       145|           80|
        152|Peter      |Hall      |PHALL   |011.44.1344.478968|2005-08-20|SA_REP    | 9000.00|          0.25|       145|           80|
        153|Christopher|Olsen     |COLSEN  |011.44.1344.498718|2006-03-30|SA_REP    | 8000.00|          0.20|       145|           80|
        156|Janette    |King      |JKING   |011.44.1345.429268|2004-01-30|SA_REP    |10000.00|          0.35|       146|           80|
        157|Patrick    |Sully     |PSULLY  |011.44.1345.929268|2004-03-04|SA_REP    | 9500.00|          0.35|       146|           80|
        158|Allan      |McEwen    |AMCEWEN |011.44.1345.829268|2004-08-01|SA_REP    | 9000.00|          0.35|       146|           80|
        159|Lindsey    |Smith     |LSMITH  |011.44.1345.729268|2005-03-10|SA_REP    | 8000.00|          0.30|       146|           80|
        162|Clara      |Vishney   |CVISHNEY|011.44.1346.129268|2005-11-11|SA_REP    |10500.00|          0.25|       147|           80|
        163|Danielle   |Greene    |DGREENE |011.44.1346.229268|2007-03-19|SA_REP    | 9500.00|          0.15|       147|           80|
        168|Lisa       |Ozer      |LOZER   |011.44.1343.929268|2005-03-11|SA_REP    |11500.00|          0.25|       148|           80|
        169|Harrison   |Bloom     |HBLOOM  |011.44.1343.829268|2006-03-23|SA_REP    |10000.00|          0.20|       148|           80|
        170|Tayler     |Fox       |TFOX    |011.44.1343.729268|2006-01-24|SA_REP    | 9600.00|          0.20|       148|           80|
        174|Ellen      |Abel      |EABEL   |011.44.1644.429267|2004-05-11|SA_REP    |11000.00|          0.30|       149|           80|
        175|Alyssa     |Hutton    |AHUTTON |011.44.1644.429266|2005-03-19|SA_REP    | 8800.00|          0.25|       149|           80|
        176|Jonathon   |Taylor    |JTAYLOR |011.44.1644.429265|2006-03-24|SA_REP    | 8600.00|          0.20|       149|           80|
        177|Jack       |Livingston|JLIVINGS|011.44.1644.429264|2006-04-23|SA_REP    | 8400.00|          0.20|       149|           80|
        204|Hermann    |Baer      |HBAER   |515.123.8888      |2002-06-07|PR_REP    |10000.00|          0.00|       101|           70|
        205|Shelley    |Higgins   |SHIGGINS|515.123.8080      |2002-06-07|AC_MGR    |12000.00|          0.00|       101|          110|
        206|William    |Gietz     |WGIETZ  |515.123.8181      |2002-06-07|AC_ACCOUNT| 8300.00|          0.00|       205|          110|

Code Explanation:

The said query in SQL that retrieves all columns from the 'employees' table where the salary is between 8000 and 12000 and commission_pct is not null, or the department_id is not in the values 40, 120, 70 and the hire_date is before June 5th, 2003.

Relational Algebra Expression:

Relational Algebra Expression: Find those employees 1. whose salary is in the range of 8000, 12000 (Begin and end values are included.) and get some commission. or 2. Those employees who joined before ‘2003-06-05’ and not included in the department number 40, 120 and 70.

Relational Algebra Tree:

Relational Algebra Tree: Find those employees 1. whose salary is in the range of 8000, 12000 (Begin and end values are included.) and get some commission. or 2. Those employees who joined before ‘2003-06-05’ and not included in the department number 40, 120 and 70.

Practice Online


HR database model

Query Visualization:

Duration:

Query visualization of Find those employees 1. whose salary is in the range of 8000, 12000 (Begin and end values are included.) and get some commission. 2. Those employees who joined before ‘2003-06-05’ and not included in the department number 40, 120 and 70 - Duration

Rows:

Query visualization of Find those employees 1. whose salary is in the range of 8000, 12000 (Begin and end values are included.) and get some commission. 2. Those employees who joined before ‘2003-06-05’ and not included in the department number 40, 120 and 70 - Rows

Cost:

Query visualization of Display all the information of employees whose salary is in the range of 8000 and 12000 and commission is not null or department number is except the number 40, 120 and 70 and they have been hired before June 5th, 2003 - Cost

Contribute your code and comments through Disqus.

Previous SQL Exercise: Employees first name does not contain the letter M .
Next SQL Exercise: Employees who does not earn any commission.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.

SQL: Tips of the Day

Difference between natural join and inner join

One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned-

Consider:

TableA                           TableB
+------------+----------+        +--------------------+    
|Column1     | Column2  |        |Column1  |  Column3 |
+-----------------------+        +--------------------+
| 1          |  2       |        | 1       |   3      |
+------------+----------+        +---------+----------+

The INNER JOIN of TableA and TableB on Column1 will return

SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1);
SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;

+------------+-----------+---------------------+    
| a.Column1  | a.Column2 | b.Column1| b.Column3|
+------------------------+---------------------+
| 1          |  2        | 1        |   3      |
+------------+-----------+----------+----------+

The NATURAL JOIN of TableA and TableB on Column1 will return:

SELECT * FROM TableA NATURAL JOIN TableB
+------------+----------+----------+    
|Column1     | Column2  | Column3  |
+-----------------------+----------+
| 1          |  2       |   3      |
+------------+----------+----------+

Ref: https://bit.ly/3AG5CId

 

We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook