SQL Exercise: Display jobs with minimum salaries over 9000
SQL SORTING and FILTERING on HR Database: Exercise-37 with Solution
37. From the following table, write a SQL query to find details of those jobs where the minimum salary exceeds 9000. Return all the fields of jobs.
Sample table: jobs
Sample Solution:
SELECT *
FROM jobs
WHERE min_salary > 9000;
Sample Output:
job_id | job_title | min_salary | max_salary ---------+-------------------------------+------------+------------ AD_PRES | President | 20000 | 40000 AD_VP | Administration Vice President | 15000 | 30000 SA_MAN | Sales Manager | 10000 | 20000 (3 rows)
Code Explanation:
The said query in SQL which selects all columns (*) from the 'jobs' table where the value in the "min_salary" column is greater than 9000. The resulting output will be all the rows from the 'jobs' table where the minimum salary is greater than 9000.
Relational Algebra Expression:
Relational Algebra Tree:
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SQL: Tips of the Day
Difference between natural join and inner join
One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned-
Consider:
TableA TableB +------------+----------+ +--------------------+ |Column1 | Column2 | |Column1 | Column3 | +-----------------------+ +--------------------+ | 1 | 2 | | 1 | 3 | +------------+----------+ +---------+----------+
The INNER JOIN of TableA and TableB on Column1 will return
SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1); SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;
+------------+-----------+---------------------+ | a.Column1 | a.Column2 | b.Column1| b.Column3| +------------------------+---------------------+ | 1 | 2 | 1 | 3 | +------------+-----------+----------+----------+
The NATURAL JOIN of TableA and TableB on Column1 will return:
SELECT * FROM TableA NATURAL JOIN TableB +------------+----------+----------+ |Column1 | Column2 | Column3 | +-----------------------+----------+ | 1 | 2 | 3 | +------------+----------+----------+
Ref: https://bit.ly/3AG5CId
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