SQL Exercise: Display jobs with minimum salaries over 9000

Last update on April 01 2023 08:57:45 (UTC/GMT +8 hours)

SQL SORTING and FILTERING on HR Database: Exercise-37 with Solution

37. From the following table, write a SQL query to find details of those jobs where the minimum salary exceeds 9000. Return all the fields of jobs.

Sample table: jobs

Sample Solution:

SELECT * 
 FROM jobs 
  WHERE min_salary > 9000;

Sample Output:

 job_id  |           job_title           | min_salary | max_salary
---------+-------------------------------+------------+------------
 AD_PRES | President                     |      20000 |      40000
 AD_VP   | Administration Vice President |      15000 |      30000
 SA_MAN  | Sales Manager                 |      10000 |      20000
(3 rows)

Code Explanation:

The said query in SQL which selects all columns (*) from the 'jobs' table where the value in the "min_salary" column is greater than 9000. The resulting output will be all the rows from the 'jobs' table where the minimum salary is greater than 9000.

Relational Algebra Expression:

Relational Algebra Tree:

Practice Online

Query Visualization:

Duration:

Rows:

Cost:

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SQL: Tips of the Day

Difference between natural join and inner join

One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned-

Consider:

TableA                           TableB
+------------+----------+        +--------------------+    
|Column1     | Column2  |        |Column1  |  Column3 |
+-----------------------+        +--------------------+
| 1          |  2       |        | 1       |   3      |
+------------+----------+        +---------+----------+

The INNER JOIN of TableA and TableB on Column1 will return

SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1);
SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;

+------------+-----------+---------------------+    
| a.Column1  | a.Column2 | b.Column1| b.Column3|
+------------------------+---------------------+
| 1          |  2        | 1        |   3      |
+------------+-----------+----------+----------+

The NATURAL JOIN of TableA and TableB on Column1 will return:

SELECT * FROM TableA NATURAL JOIN TableB
+------------+----------+----------+    
|Column1     | Column2  | Column3  |
+-----------------------+----------+
| 1          |  2       |   3      |
+------------+----------+----------+

Ref: https://bit.ly/3AG5CId

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