SQL Exercise: Employees have the given letters in their first name
SQL SORTING and FILTERING on HR Database: Exercise-17 with Solution
17. From the following table, write a SQL query to find employees whose first names contain the letters D, S, or N. Sort the result-set in descending order by salary. Return all fields.
Sample table : employees
Sample Solution:
SELECT *
FROM employees
WHERE first_name LIKE '%D%'
OR first_name LIKE '%S%'
OR first_name LIKE '%N%'
ORDER BY salary DESC;
Sample Output:
employee_id | first_name | last_name | email | phone_number | hire_date | job_id | salary | commission_pct | manager_id | department_id -------------+------------+-----------+----------+--------------------+------------+------------+----------+----------------+------------+--------------- 100 | Steven | King | SKING | 515.123.4567 | 2003-06-17 | AD_PRES | 24000.00 | 0.00 | 0 | 90 101 | Neena | Kochhar | NKOCHHAR | 515.123.4568 | 2005-09-21 | AD_VP | 17000.00 | 0.00 | 100 | 90 205 | Shelley | Higgins | SHIGGINS | 515.123.8080 | 2002-06-07 | AC_MGR | 12000.00 | 0.00 | 101 | 110 108 | Nancy | Greenberg | NGREENBE | 515.124.4569 | 2002-08-17 | FI_MGR | 12000.00 | 0.00 | 101 | 100 114 | Den | Raphaely | DRAPHEAL | 515.127.4561 | 2002-12-07 | PU_MAN | 11000.00 | 0.00 | 100 | 30 151 | David | Bernstein | DBERNSTE | 011.44.1344.345268 | 2005-03-24 | SA_REP | 9500.00 | 0.25 | 145 | 80 163 | Danielle | Greene | DGREENE | 011.44.1346.229268 | 2007-03-19 | SA_REP | 9500.00 | 0.15 | 147 | 80 109 | Daniel | Faviet | DFAVIET | 515.124.4169 | 2002-08-16 | FI_ACCOUNT | 9000.00 | 0.00 | 108 | 100 154 | Nanette | Cambrault | NCAMBRAU | 011.44.1344.987668 | 2006-12-09 | SA_REP | 7500.00 | 0.20 | 145 | 80 161 | Sarath | Sewall | SSEWALL | 011.44.1345.529268 | 2006-11-03 | SA_REP | 7000.00 | 0.25 | 146 | 80 165 | David | Lee | DLEE | 011.44.1346.529268 | 2008-02-23 | SA_REP | 6800.00 | 0.10 | 147 | 80 123 | Shanta | Vollman | SVOLLMAN | 650.123.4234 | 2005-10-10 | ST_MAN | 6500.00 | 0.00 | 100 | 50 203 | Susan | Mavris | SMAVRIS | 515.123.7777 | 2002-06-07 | HR_REP | 6500.00 | 0.00 | 101 | 40 166 | Sundar | Ande | SANDE | 011.44.1346.629268 | 2008-03-24 | SA_REP | 6400.00 | 0.10 | 147 | 80 173 | Sundita | Kumar | SKUMAR | 011.44.1343.329268 | 2008-04-21 | SA_REP | 6100.00 | 0.10 | 148 | 80 105 | David | Austin | DAUSTIN | 590.423.4569 | 2005-06-25 | IT_PROG | 4800.00 | 0.00 | 103 | 60 184 | Nandita | Sarchand | NSARCHAN | 650.509.1876 | 2004-01-27 | SH_CLERK | 4200.00 | 0.00 | 121 | 50 107 | Diana | Lorentz | DLORENTZ | 590.423.5567 | 2007-02-07 | IT_PROG | 4200.00 | 0.00 | 103 | 60 192 | Sarah | Bell | SBELL | 650.501.1876 | 2004-02-04 | SH_CLERK | 4000.00 | 0.00 | 123 | 50 194 | Samuel | McCain | SMCCAIN | 650.501.3876 | 2006-07-01 | SH_CLERK | 3200.00 | 0.00 | 123 | 50 138 | Stephen | Stiles | SSTILES | 650.121.2034 | 2005-10-26 | ST_CLERK | 3200.00 | 0.00 | 123 | 50 116 | Shelli | Baida | SBAIDA | 515.127.4563 | 2005-12-24 | PU_CLERK | 2900.00 | 0.00 | 114 | 30 117 | Sigal | Tobias | STOBIAS | 515.127.4564 | 2005-07-24 | PU_CLERK | 2800.00 | 0.00 | 114 | 30 198 | Donald | OConnell | DOCONNEL | 650.507.9833 | 2007-06-21 | SH_CLERK | 2600.00 | 0.00 | 124 | 50 199 | Douglas | Grant | DGRANT | 650.507.9844 | 2008-01-13 | SH_CLERK | 2600.00 | 0.00 | 124 | 50 128 | Steven | Markle | SMARKLE | 650.124.1434 | 2008-03-08 | ST_CLERK | 2200.00 | 0.00 | 120 | 50 (26 rows)
Code Explanation:
The said query in SQL that retrieves all columns (*) from the 'employees' table where the value in the "first_name" column contains either "D", "S", or "N". The result is sorted in descending order based on the values in the "salary" column. There will be a set of rows in the "employees" table whose first names match the pattern specified, sorted from the highest to the lowest salary, that will appear in the employee table.
Relational Algebra Expression:
Relational Algebra Tree:
Practice Online

Query Visualization:
Duration:

Rows:

Cost:

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Previous SQL Exercise: Find employees whose managers are hold given IDs.
Next SQL Exercise: Employees earn over 11000 or 7th digit in their phone.
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SQL: Tips of the Day
Difference between natural join and inner join
One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned-
Consider:
TableA TableB +------------+----------+ +--------------------+ |Column1 | Column2 | |Column1 | Column3 | +-----------------------+ +--------------------+ | 1 | 2 | | 1 | 3 | +------------+----------+ +---------+----------+
The INNER JOIN of TableA and TableB on Column1 will return
SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1); SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;
+------------+-----------+---------------------+ | a.Column1 | a.Column2 | b.Column1| b.Column3| +------------------------+---------------------+ | 1 | 2 | 1 | 3 | +------------+-----------+----------+----------+
The NATURAL JOIN of TableA and TableB on Column1 will return:
SELECT * FROM TableA NATURAL JOIN TableB +------------+----------+----------+ |Column1 | Column2 | Column3 | +-----------------------+----------+ | 1 | 2 | 3 | +------------+----------+----------+
Ref: https://bit.ly/3AG5CId
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