SQL Exercise: Find employees who works either in department 70 or 90
SQL SORTING and FILTERING on HR Database: Exercise-13 with Solution
13. From the following table, write a SQL query to find those employees who work either in department 70 or 90. Return full name (first and last name), department id.
Sample table : employees
Sample Solution:
SELECT first_name ||' '|| last_name AS Full_Name, department_id
FROM employees
WHERE department_id = 70
OR department_id = 90;
OR
SELECT first_name ||' '|| last_name AS Full_Name, department_id
FROM employees
WHERE department_id IN (70 , 90);
Sample Output:
full_name | department_id ---------------+--------------- Steven King | 90 Neena Kochhar | 90 Lex De Haan | 90 Hermann Baer | 70 (4 rows)
Code Explanation:
The said query in SQL that retrieves the first name and last name concatenated as "Full_Name" and the "department_id" from the 'employees' table where the "department_id" is either 70 or 90.
Practice Online

Query Visualization for Sample Solution:
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Query Visualization for alternate Sample Solution:
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Previous SQL Exercise: Employees who was hired during given dates.
Next SQL Exercise: Find those employees who is working under a manager.
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SQL: Tips of the Day
Difference between natural join and inner join
One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned-
Consider:
TableA TableB +------------+----------+ +--------------------+ |Column1 | Column2 | |Column1 | Column3 | +-----------------------+ +--------------------+ | 1 | 2 | | 1 | 3 | +------------+----------+ +---------+----------+
The INNER JOIN of TableA and TableB on Column1 will return
SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1); SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;
+------------+-----------+---------------------+ | a.Column1 | a.Column2 | b.Column1| b.Column3| +------------------------+---------------------+ | 1 | 2 | 1 | 3 | +------------+-----------+----------+----------+
The NATURAL JOIN of TableA and TableB on Column1 will return:
SELECT * FROM TableA NATURAL JOIN TableB +------------+----------+----------+ |Column1 | Column2 | Column3 | +-----------------------+----------+ | 1 | 2 | 3 | +------------+----------+----------+
Ref: https://bit.ly/3AG5CId
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