SQL exercises on movie Database: Find the ID number for the actor whose first name is 'Woody' and the last name is 'Allen'
SQL movie Database: Basic Exercise-10 with Solution
10. From the following table, write a SQL query to find those actors with the first name 'Woody' and the last name 'Allen'. Return actor ID.
Sample table: actoract_id | act_fname | act_lname | act_gender --------+----------------------+----------------------+------------ 101 | James | Stewart | M 102 | Deborah | Kerr | F 103 | Peter | OToole | M 104 | Robert | De Niro | M 105 | F. Murray | Abraham | M 106 | Harrison | Ford | M 107 | Nicole | Kidman | F 108 | Stephen | Baldwin | M 109 | Jack | Nicholson | M 110 | Mark | Wahlberg | M 111 | Woody | Allen | M 112 | Claire | Danes | F 113 | Tim | Robbins | M 114 | Kevin | Spacey | M 115 | Kate | Winslet | F 116 | Robin | Williams | M 117 | Jon | Voight | M 118 | Ewan | McGregor | M 119 | Christian | Bale | M 120 | Maggie | Gyllenhaal | F 121 | Dev | Patel | M 122 | Sigourney | Weaver | F 123 | David | Aston | M 124 | Ali | Astin | F
Sample Solution:
-- Selecting 'act_id' from the 'actor' table
-- Filtering results where 'act_fname' is 'Woody' and 'act_lname' is 'Allen'
SELECT act_id
FROM actor
WHERE act_fname='Woody'
AND act_lname='Allen';
Sample Output:
act_id -------- 111 (1 row)
Code Explanation:
The said query in SQL that select the act_id of an actor with the first name 'Woody' and the last name 'Allen' from a table named 'actor'. The query filters the results using the WHERE clause to match only the rows that meet the said criteria.
Relational Algebra Expression:
Relational Algebra Tree:
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Query Visualization:
Duration:
Rows:
Cost:
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