SQL Exercise: Departments which does not have any employee
SQL JOINS on HR Database: Exercise-6 with Solution
6. From the following tables, write a SQL query to find all departments, including those without employees. Return first name, last name, department ID, department name.
Sample table: departments
Sample table: employees
Sample Solution:
-- Selecting specific columns (E.first_name, E.last_name, D.department_id, D.department_name) from the 'employees' table, aliased as 'E', and the 'departments' table, aliased as 'D'
SELECT E.first_name, E.last_name, D.department_id, D.department_name
-- Performing a RIGHT OUTER JOIN between the 'employees' table (aliased as 'E') and the 'departments' table (aliased as 'D') based on the 'department_id' column
FROM employees E
RIGHT OUTER JOIN departments D
ON E.department_id = D.department_id;
Sample Output:
first_name | last_name | department_id | department_name -------------+-------------+---------------+---------------------- Steven | King | 90 | Executive Neena | Kochhar | 90 | Executive Lex | De Haan | 90 | Executive Alexander | Hunold | 60 | IT Bruce | Ernst | 60 | IT David | Austin | 60 | IT Valli | Pataballa | 60 | IT Diana | Lorentz | 60 | IT Nancy | Greenberg | 100 | Finance Daniel | Faviet | 100 | Finance John | Chen | 100 | Finance Ismael | Sciarra | 100 | Finance Jose Manuel | Urman | 100 | Finance Luis | Popp | 100 | Finance Den | Raphaely | 30 | Purchasing Alexander | Khoo | 30 | Purchasing Shelli | Baida | 30 | Purchasing Sigal | Tobias | 30 | Purchasing Guy | Himuro | 30 | Purchasing Karen | Colmenares | 30 | Purchasing Matthew | Weiss | 50 | Shipping Adam | Fripp | 50 | Shipping Payam | Kaufling | 50 | Shipping Shanta | Vollman | 50 | Shipping Kevin | Mourgos | 50 | Shipping Julia | Nayer | 50 | Shipping Irene | Mikkilineni | 50 | Shipping James | Landry | 50 | Shipping Steven | Markle | 50 | Shipping Laura | Bissot | 50 | Shipping Mozhe | Atkinson | 50 | Shipping James | Marlow | 50 | Shipping TJ | Olson | 50 | Shipping Jason | Mallin | 50 | Shipping Michael | Rogers | 50 | Shipping Ki | Gee | 50 | Shipping Hazel | Philtanker | 50 | Shipping Renske | Ladwig | 50 | Shipping Stephen | Stiles | 50 | Shipping John | Seo | 50 | Shipping Joshua | Patel | 50 | Shipping Trenna | Rajs | 50 | Shipping Curtis | Davies | 50 | Shipping Randall | Matos | 50 | Shipping Peter | Vargas | 50 | Shipping John | Russell | 80 | Sales Karen | Partners | 80 | Sales Alberto | Errazuriz | 80 | Sales Gerald | Cambrault | 80 | Sales Eleni | Zlotkey | 80 | Sales Peter | Tucker | 80 | Sales David | Bernstein | 80 | Sales Peter | Hall | 80 | Sales Christopher | Olsen | 80 | Sales Nanette | Cambrault | 80 | Sales Oliver | Tuvault | 80 | Sales Janette | King | 80 | Sales Patrick | Sully | 80 | Sales Allan | McEwen | 80 | Sales Lindsey | Smith | 80 | Sales Louise | Doran | 80 | Sales Sarath | Sewall | 80 | Sales Clara | Vishney | 80 | Sales Danielle | Greene | 80 | Sales Mattea | Marvins | 80 | Sales David | Lee | 80 | Sales Sundar | Ande | 80 | Sales Amit | Banda | 80 | Sales Lisa | Ozer | 80 | Sales Harrison | Bloom | 80 | Sales Tayler | Fox | 80 | Sales William | Smith | 80 | Sales Elizabeth | Bates | 80 | Sales Sundita | Kumar | 80 | Sales Ellen | Abel | 80 | Sales Alyssa | Hutton | 80 | Sales Jonathon | Taylor | 80 | Sales Jack | Livingston | 80 | Sales Charles | Johnson | 80 | Sales Winston | Taylor | 50 | Shipping Jean | Fleaur | 50 | Shipping Martha | Sullivan | 50 | Shipping Girard | Geoni | 50 | Shipping Nandita | Sarchand | 50 | Shipping Alexis | Bull | 50 | Shipping Julia | Dellinger | 50 | Shipping Anthony | Cabrio | 50 | Shipping Kelly | Chung | 50 | Shipping Jennifer | Dilly | 50 | Shipping Timothy | Gates | 50 | Shipping Randall | Perkins | 50 | Shipping Sarah | Bell | 50 | Shipping Britney | Everett | 50 | Shipping Samuel | McCain | 50 | Shipping Vance | Jones | 50 | Shipping Alana | Walsh | 50 | Shipping Kevin | Feeney | 50 | Shipping Donald | OConnell | 50 | Shipping Douglas | Grant | 50 | Shipping Jennifer | Whalen | 10 | Administration Michael | Hartstein | 20 | Marketing Pat | Fay | 20 | Marketing Susan | Mavris | 40 | Human Resources Hermann | Baer | 70 | Public Relations Shelley | Higgins | 110 | Accounting William | Gietz | 110 | Accounting | | 200 | Operations | | 130 | Corporate Tax | | 160 | Benefits | | 270 | Payroll | | 260 | Recruiting | | 120 | Treasury | | 250 | Retail Sales | | 210 | IT Support | | 230 | IT Helpdesk | | 190 | Contracting | | 170 | Manufacturing | | 240 | Government Sales | | 150 | Shareholder Services | | 180 | Construction | | 220 | NOC | | 140 | Control And Credit (122 rows)
Code Explanation:
The said query in SQL that selects the first name, last name, department ID, and department name of all departments and their employees, including departments that have no employees. The query retrieves data from the employees and departments tables.
The RIGHT OUTER JOIN clause joins the departments table with the employees table using the department_id column, which is common to both tables. This type of join returns all rows from the right table that is departments, and the matching rows from the left table that is employees, and if there is no match on the left table, it returns NULL values for the columns of that table.
Relational Algebra Expression:
Relational Algebra Tree:
Visual Presentation:
Alternative Solutions:
Using LEFT JOIN:
SELECT E.first_name, E.last_name, D.department_id, D.department_name
FROM departments D
LEFT JOIN employees E ON E.department_id = D.department_id;
Using INNER JOIN and UNION ALL:
SELECT E.first_name, E.last_name, D.department_id, D.department_name
FROM employees E
INNER JOIN departments D ON E.department_id = D.department_id
UNION ALL
SELECT NULL AS first_name, NULL AS last_name, D.department_id, D.department_name
FROM departments D
WHERE NOT EXISTS (
SELECT 1
FROM employees E
WHERE E.department_id = D.department_id
);
Practice Online
Query Visualization:
Duration:
Rows:
Cost:
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Previous SQL Exercise: Employees who contain a letter z to their first name.
Next SQL Exercise: Employees who earn less than employee 182.
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