SQL Exercise: Physicians, a medical procedure without certification

Last update on June 05 2024 06:06:49 (UTC/GMT +8 hours)

SQL hospital Database: Exercise-31 with Solution

31. From the following tables, write a SQL query to find all physicians who have performed a medical procedure but are not certified to do so. Return Physician name as "Physician".

Sample table: physician

 employeeid |       name        |           position           |    ssn
------------+-------------------+------------------------------+-----------
          1 | John Dorian       | Staff Internist              | 111111111
          2 | Elliot Reid       | Attending Physician          | 222222222
          3 | Christopher Turk  | Surgical Attending Physician | 333333333
          4 | Percival Cox      | Senior Attending Physician   | 444444444
          5 | Bob Kelso         | Head Chief of Medicine       | 555555555
          6 | Todd Quinlan      | Surgical Attending Physician | 666666666
          7 | John Wen          | Surgical Attending Physician | 777777777
          8 | Keith Dudemeister | MD Resident                  | 888888888
          9 | Molly Clock       | Attending Psychiatrist       | 999999999

Sample table: undergoes

 physician | treatment | certificationdate | certificationexpires
-----------+-----------+-------------------+----------------------
         3 |         1 | 2008-01-01        | 2008-12-31
         3 |         2 | 2008-01-01        | 2008-12-31
         3 |         5 | 2008-01-01        | 2008-12-31
         3 |         6 | 2008-01-01        | 2008-12-31
         3 |         7 | 2008-01-01        | 2008-12-31
         6 |         2 | 2008-01-01        | 2008-12-31
         6 |         5 | 2007-01-01        | 2007-12-31
         6 |         6 | 2008-01-01        | 2008-12-31
         7 |         1 | 2008-01-01        | 2008-12-31
         7 |         2 | 2008-01-01        | 2008-12-31
         7 |         3 | 2008-01-01        | 2008-12-31
         7 |         4 | 2008-01-01        | 2008-12-31
         7 |         5 | 2008-01-01        | 2008-12-31
         7 |         6 | 2008-01-01        | 2008-12-31
         7 |         7 | 2008-01-01        | 2008-12-31

Sample table: trained_in

 physician | treatment | certificationdate | certificationexpires
-----------+-----------+-------------------+----------------------
         3 |         1 | 2008-01-01        | 2008-12-31
         3 |         2 | 2008-01-01        | 2008-12-31
         3 |         5 | 2008-01-01        | 2008-12-31
         3 |         6 | 2008-01-01        | 2008-12-31
         3 |         7 | 2008-01-01        | 2008-12-31
         6 |         2 | 2008-01-01        | 2008-12-31
         6 |         5 | 2007-01-01        | 2007-12-31
         6 |         6 | 2008-01-01        | 2008-12-31
         7 |         1 | 2008-01-01        | 2008-12-31
         7 |         2 | 2008-01-01        | 2008-12-31
         7 |         3 | 2008-01-01        | 2008-12-31
         7 |         4 | 2008-01-01        | 2008-12-31
         7 |         5 | 2008-01-01        | 2008-12-31
         7 |         6 | 2008-01-01        | 2008-12-31
         7 |         7 | 2008-01-01        | 2008-12-31

Sample Solution:

SELECT name AS "Physician"
FROM physician
WHERE employeeid IN
    ( SELECT undergoes.physician
     FROM undergoes
     LEFT JOIN trained_In ON undergoes.physician=trained_in.physician
     AND undergoes.procedure=trained_in.treatment
     WHERE treatment IS NULL );

Sample Output:

    Physician
------------------
 Christopher Turk
(1 row)

Explanation:

The said query in SQL retrieves the name of physicians who have not been trained in a particular medical procedure by looking for records in the 'undergoes' table where a corresponding record in the 'trained_in' table with the same physician and procedure does not exist.

From the outer query filters the results by selecting only those records where the "employeeid" column is found in a subquery.

In the subquery the LEFT JOIN keyword joins the 'undergoes' and 'trained_in' tables based on the common columns physician, procedure, and treatment.

The WHERE clause in the subquery filters the results of the join to include only those records where "treatment" is NULL.

Practice Online

E R Diagram of Hospital Database:

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