SQL Exercise: Name of the patients, their block, floor, room number

SQL hospital Database: Exercise-28 with Solution

28. From the following tables, write a SQL query to find the name of the patients, their block, floor, and room number where they admitted.

 stayid |  patient  | room |     start_time      |      end_time
--------+-----------+------+---------------------+---------------------
   3215 | 100000001 |  111 | 2008-05-01 00:00:00 | 2008-05-04 00:00:00
   3216 | 100000003 |  123 | 2008-05-03 00:00:00 | 2008-05-14 00:00:00
   3217 | 100000004 |  112 | 2008-05-02 00:00:00 | 2008-05-03 00:00:00

    ssn    |       name        |      address       |  phone   | insuranceid | pcp
-----------+-------------------+--------------------+----------+-------------+-----
 100000001 | John Smith        | 42 Foobar Lane     | 555-0256 |    68476213 |   1
 100000002 | Grace Ritchie     | 37 Snafu Drive     | 555-0512 |    36546321 |   2
 100000003 | Random J. Patient | 101 Omgbbq Street  | 555-1204 |    65465421 |   2
 100000004 | Dennis Doe        | 1100 Foobaz Avenue | 555-2048 |    68421879 |   3

roomnumber | roomtype | blockfloor | blockcode | unavailable
-----------+----------+------------+-----------+-------------
       101 | Single   |          1 |         1 | f
       102 | Single   |          1 |         1 | f
       103 | Single   |          1 |         1 | f
       111 | Single   |          1 |         2 | f
       112 | Single   |          1 |         2 | t
       113 | Single   |          1 |         2 | f
       121 | Single   |          1 |         3 | f
       122 | Single   |          1 |         3 | f
       123 | Single   |          1 |         3 | f
       201 | Single   |          2 |         1 | t
       202 | Single   |          2 |         1 | f
       203 | Single   |          2 |         1 | f
       211 | Single   |          2 |         2 | f
       212 | Single   |          2 |         2 | f
       213 | Single   |          2 |         2 | t
       221 | Single   |          2 |         3 | f
       222 | Single   |          2 |         3 | f
       223 | Single   |          2 |         3 | f
       301 | Single   |          3 |         1 | f
       302 | Single   |          3 |         1 | t
       303 | Single   |          3 |         1 | f
       311 | Single   |          3 |         2 | f
       312 | Single   |          3 |         2 | f
       313 | Single   |          3 |         2 | f
       321 | Single   |          3 |         3 | t
       322 | Single   |          3 |         3 | f
       323 | Single   |          3 |         3 | f
       401 | Single   |          4 |         1 | f
       402 | Single   |          4 |         1 | t
       403 | Single   |          4 |         1 | f
       411 | Single   |          4 |         2 | f
       412 | Single   |          4 |         2 | f
       413 | Single   |          4 |         2 | f
       421 | Single   |          4 |         3 | t
       422 | Single   |          4 |         3 | f
       423 | Single   |          4 |         3 | f

Sample Solution:

SELECT p.name AS "Patient",
       s.room AS "Room",
       r.blockfloor AS "Floor",
       r.blockcode AS "Block"
FROM stay s
JOIN patient p ON s.patient=p.ssn
JOIN room r ON s.room=r.roomnumber;

Sample Output:

      Patient      | Room | Floor | Block
-------------------+------+-------+-------
 John Smith        |  111 |     1 |     2
 Random J. Patient |  123 |     1 |     3
 Dennis Doe        |  112 |     1 |     2
(3 rows)

Explanation:

The said query in SQL that retrieves the name of the patient, the room number they are staying in, and the floor and block of that room.

The JOIN keyword joins the patient table to the stay table based on the ssn and patient columns and the room table to the stay table based on the roomnumber and room columns.

Practice Online

E R Diagram of Hospital Database:

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