SQL Exercise: List the result in descending order of salary
SQL subqueries on employee Database: Exercise-11 with Solution
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11. From the following table, write a SQL query to find those employees whose salary is the same as the salary of FRANK or SANDRINE. Sort the result-set in descending order by salary. Return complete information about the employees.
Sample table: employees
Sample Solution:
SELECT *
FROM employees
WHERE salary IN
(SELECT salary
FROM employees e
WHERE e.emp_name IN ('FRANK',
'BLAZE')
AND employees.emp_id <> e.emp_id);
OR
SELECT *
FROM employees
WHERE salary IN
(SELECT salary
FROM employees e
WHERE (emp_name = 'FRANK'
OR emp_name = 'BLAZE')
AND employees.emp_id <> e.emp_id)
ORDER BY salary DESC;
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 (1 row)
Explanation:
The given query in SQL that selects all employees whose salary is equal to the salary of either 'FRANK' or 'BLAZE', but not including their own salary from the 'employees' table.
The WHERE clause in the main query, which filters the results to only include rows where the salary is found in the salaries of either 'FRANK' or 'BLAZE', but not including their own salary determined by the subquery. The subquery, which selects the salaries of the employees named 'FRANK' and 'BLAZE' from the 'employees' table and excludes the salary of the current employee.
Practice Online
Structure of employee Database:
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Previous SQL Exercise: Personnel with department ID 2001 and ID 1001.
Next SQL Exercise: Designation or salaries exceed match Marker or Adelyn's.
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