SQL Exercise: Number of employee for each job in each department
SQL employee Database: Exercise-97 with Solution
[An editor is available at the bottom of the page to write and execute the scripts.]
97. From the following table, write a SQL query to count the number of employees in each designation of a department. Return department id, job name and number of employees.
Sample table: employees
Sample Solution:
SELECT dep_id,
job_name,
count(*)
FROM employees
GROUP BY dep_id,
job_name;
Sample Output:
dep_id | job_name | count --------+-----------+------- 3001 | MANAGER | 1 2001 | ANALYST | 2 3001 | SALESMAN | 4 1001 | MANAGER | 1 1001 | PRESIDENT | 1 2001 | MANAGER | 1 2001 | CLERK | 2 1001 | CLERK | 1 3001 | CLERK | 1 (9 rows)
Explanation:
The given query in SQL that retrieves "dep_id" ,"job_name" and the count of employees in each department and job name, but only for those who were hired on or after January 1st, 2022 from the table 'employees'.
It groups the data by the combination of columns "dep_id" and "job_name", and counts the number of records for each combination.
Relational Algebra Expression:
Relational Algebra Tree:
Practice Online
Sample Database: employee
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous SQL Exercise: In ASC order, list managers and count their employees.
Next SQL Exercise: List the department where at least two employees work.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
It will be nice if you may share this link in any developer community or anywhere else, from where other developers may find this content. Thanks.
https://w3resource.com/sql-exercises/employee-database-exercise/sql-employee-database-exercise-97.php
- Weekly Trends and Language Statistics
- Weekly Trends and Language Statistics