SQL Exercise: Employees joining on given days, ascending in seniority

Last update on December 20 2024 11:40:37 (UTC/GMT +8 hours)

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72. From the following table, write a SQL query to find those employees who joined on 1-MAY-91, or 3-DEC-91, or 19-JAN-90. Sort the result-set in ascending order by hire date. Return complete information about the employees.

Pictorial Presentation:

Sample table: employees

Sample Solution:

SELECT *
FROM employees
WHERE hire_date IN ('1991-5-01',
                    '1991-12-03',
                    '1990-01-19')
ORDER BY hire_date ASC;

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
  66928 | BLAZE    | MANAGER  |      68319 | 1991-05-01 | 2750.00 |            |   3001
  69062 | FRANK    | ANALYST  |      65646 | 1991-12-03 | 3100.00 |            |   2001
  69000 | JULIUS   | CLERK    |      66928 | 1991-12-03 | 1050.00 |            |   3001
(3 rows)

Explanation:

The said query in SQL that returns all the rows and columns from the 'employees' table where the "hire_date" column matches either '1991-5-01', '1991-12-03', or '1990-01-19', and sorts the result set in ascending order on "hire_date" column.

Relational Algebra Expression:

Relational Algebra Tree:

Practice Online

Sample Database: employee

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