SQL Exercise: Employees who joined in a given month having char A
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114. From the following table, write a SQL query to find those employees who joined in any month, but the month name contain the character ‘A’. Return complete information about the employees.
Sample table: employees
Sample Solution:
SELECT *
FROM employees
WHERE to_char (hire_date,'MONTH') LIKE '%A%';
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 (7 rows)
Explanation:
The said query in SQL that returns all rows where the "hire_date" month contains the letter "A" in any position within the month name from the 'employees' table. The "to_char" function converts the "hire_date" column to a string in the format "MONTH", which returns the full name of the month.
Practice Online
Sample Database: employee
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