SQL Exercise: Employees who joined in a given month having char A

Last update on December 20 2024 11:59:28 (UTC/GMT +8 hours)

[An editor is available at the bottom of the page to write and execute the scripts.]

114. From the following table, write a SQL query to find those employees who joined in any month, but the month name contain the character ‘A’. Return complete information about the employees.

Sample table: employees

Sample Solution:

SELECT *
FROM employees
WHERE to_char (hire_date,'MONTH') LIKE '%A%';

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
  66928 | BLAZE    | MANAGER  |      68319 | 1991-05-01 | 2750.00 |            |   3001
  65646 | JONAS    | MANAGER  |      68319 | 1991-04-02 | 2957.00 |            |   2001
  67858 | SCARLET  | ANALYST  |      65646 | 1997-04-19 | 3100.00 |            |   2001
  64989 | ADELYN   | SALESMAN |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
  65271 | WADE     | SALESMAN |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001
  68736 | ADNRES   | CLERK    |      67858 | 1997-05-23 | 1200.00 |            |   2001
  69324 | MARKER   | CLERK    |      67832 | 1992-01-23 | 1400.00 |            |   1001
(7 rows)

Explanation:

The said query in SQL that returns all rows where the "hire_date" month contains the letter "A" in any position within the month name from the 'employees' table. The "to_char" function converts the "hire_date" column to a string in the format "MONTH", which returns the full name of the month.

Practice Online

Sample Database: employee

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous SQL Exercise: List the Employees whose names end with S and length 6.
Next SQL Exercise: Employees who joined in a month having 2nd char is A.