SQL Exercise: Employee start with 'A' and end with 'N', length six

Last update on October 09 2025 12:42:26 (UTC/GMT +8 hours)

[An editor is available at the bottom of the page to write and execute the scripts.]

107. From the following table, write a SQL query to find those employees whose name is six characters in length, starting with 'A' and ending with 'N'. Return number of employees.

Sample table: employees

Sample Solution:

SELECT *
FROM employees
WHERE length(emp_name)=6
  AND emp_name LIKE 'A%N';

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
  64989 | ADELYN   | SALESMAN |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
(1 row)

Explanation:

The said query in SQL that selects all columns of employees whose names have a length of 6 characters and start with the letter 'A' and end with the letter 'N' from the employees table.

With the WHERE clause, the length() function is used to verify that emp_name contains exactly six characters, and the LIKE operator is used to match names that begin with A and end with 'N'.

Go to:

PREV : Six-character employee names with R in 3rd position.
NEXT : Employees joined with a as the 2nd character of a month.

Practice Online

Sample Database: employee

Have another way to solve this solution? Contribute your code (and comments) through Disqus.