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SQL Challenges-1: Writers who rated more than one topics on the same date

SQL Challenges-1: Exercise-40 with Solution

From the following table write a SQL query to find all the writers who rated more than one topics on the same date, sorted in ascending order by their id. Return writr ID.

Input:

Table: topics

Structure:

FieldTypeNullKeyDefaultExtra
topic_idint(11)YES
writer_idint(11)YES
rated_byint(11)YES
date_of_ratingdateYES

Data:

topic_idwriter_idrated_bydate_of_rating
100015045072020-07-17
100035025032020-09-22
10001503507 2020-12-23
10002501507 2020-07-17
100025025022020-04-10
100025045022020-11-16
10003501502 2020-04-10
10001507507 2020-12-23
100045035012020-08-28
100035055042020-12-21

Sample Solution:

SQL Code(MySQL):

CREATE TABLE topics (topic_id int, writer_id int, rated_by int, date_of_rating date);
INSERT INTO topics VALUES (10001,504,507,'2020-07-17');
INSERT INTO topics VALUES (10003,502,503,'2020-09-22'); 
INSERT INTO topics VALUES (10001,503,507,'2020-12-23'); 
INSERT INTO topics VALUES (10002,501,507,'2020-07-17'); 
INSERT INTO topics VALUES (10002,502,502,'2020-04-10'); 
INSERT INTO topics VALUES (10002,504,502,'2020-11-16'); 
INSERT INTO topics VALUES (10003,501,502,'2020-04-10'); 
INSERT INTO topics VALUES (10001,507,507,'2020-10-23'); 
INSERT INTO topics VALUES (10004,503,501,'2020-08-28'); 
INSERT INTO topics VALUES (10003,505,504,'2020-12-21'); 


SELECT DISTINCT rated_by AS 'Topic rated by the writer' 
FROM topics
GROUP BY rated_by, date_of_rating 
HAVING COUNT(DISTINCT topic_id) > 1
ORDER BY 1

Sample Output:

Topic rated by the writer|
-------------------------|
                      502|
                      507|

SQL Code Editor:


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