AdventureWorks Database: Return the five leftmost characters of each product name
62. From the following table write a query in SQL to return the five leftmost characters of each product name.
Sample table: production.productproductid|name |productnumber|makeflag|finishedgoodsflag|color |safetystocklevel|reorderpoint|standardcost|listprice|size|sizeunitmeasurecode|weightunitmeasurecode|weight |daystomanufacture|productline|class|style|productsubcategoryid|productmodelid|sellstartdate |sellenddate |discontinueddate|rowguid |modifieddate | ---------+--------------------------------+-------------+--------+-----------------+------------+----------------+------------+------------+---------+----+-------------------+---------------------+-------+-----------------+-----------+-----+-----+--------------------+--------------+-----------------------+-----------------------+----------------+------------------------------------+-----------------------+ 1|Adjustable Race |AR-5381 |false |false | | 1000| 750| 0| 0| | | | | 0| | | | | |2008-04-30 00:00:00.000| | |694215b7-08f7-4c0d-acb1-d734ba44c0c8|2014-02-08 10:01:36.827| 2|Bearing Ball |BA-8327 |false |false | | 1000| 750| 0| 0| | | | | 0| | | | | |2008-04-30 00:00:00.000| | |58ae3c20-4f3a-4749-a7d4-d568806cc537|2014-02-08 10:01:36.827| 3|BB Ball Bearing |BE-2349 |true |false | | 800| 600| 0| 0| | | | | 1| | | | | |2008-04-30 00:00:00.000| | |9c21aed2-5bfa-4f18-bcb8-f11638dc2e4e|2014-02-08 10:01:36.827| 4|Headset Ball Bearings |BE-2908 |false |false | | 800| 600| 0| 0| | | | | 0| | | | | |2008-04-30 00:00:00.000| | |ecfed6cb-51ff-49b5-b06c-7d8ac834db8b|2014-02-08 10:01:36.827| 316|Blade |BL-2036 |true |false | | 800| 600| 0| 0| | | | | 1| | | | | |2008-04-30 00:00:00.000| | |e73e9750-603b-4131-89f5-3dd15ed5ff80|2014-02-08 10:01:36.827| 317|LL Crankarm |CA-5965 |false |false |Black | 500| 375| 0| 0| | | | | 0| |L | | | |2008-04-30 00:00:00.000| | |3c9d10b7-a6b2-4774-9963-c19dcee72fea|2014-02-08 10:01:36.827| 318|ML Crankarm |CA-6738 |false |false |Black | 500| 375| 0| 0| | | | | 0| |M | | | |2008-04-30 00:00:00.000| | |eabb9a92-fa07-4eab-8955-f0517b4a4ca7|2014-02-08 10:01:36.827| -- more --
Sample Solution:
-- Selecting the leftmost 5 characters of the 'Name' column
SELECT LEFT(Name, 5)
-- From the Production schema's Product table
FROM Production.Product
-- Ordering the result set by the 'ProductID' column
ORDER BY ProductID;
Explanation:
- The SQL query retrieves data from the Product table within the Production schema.
- It uses the LEFT() function to extract the leftmost 5 characters of the Name column.
- The LEFT() function is used to return a specified number of characters from the left side of a string.
- The result set is ordered by the ProductID column.
Sample Output:
left | -----+ Adjus| Beari| BB Ba| Heads| Blade| LL Cr| ML Cr| HL Cr| Chain| Chain| Chain| ...
SQL AdventureWorks Editor:
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