AdventureWorks Database: Return the highest hourly wage for each job title

Last update on June 03 2024 13:23:23 (UTC/GMT +8 hours)

SQL Query - AdventureWorks: Exercise-125 with Solution

125. From the following tables write a query in SQL to return the highest hourly wage for each job title. Restricts the titles to those that are held by men with a maximum pay rate greater than 40 dollars or women with a maximum pay rate greater than 42 dollars.

Sample table: HumanResources.Employee

businessentityid|nationalidnumber|loginid                     |jobtitle                                |birthdate |maritalstatus|gender|hiredate  |salariedflag|vacationhours|sickleavehours|currentflag|rowguid                             |modifieddate           |organizationnode|
----------------+----------------+----------------------------+----------------------------------------+----------+-------------+------+----------+------------+-------------+--------------+-----------+------------------------------------+-----------------------+----------------+
               1|295847284       |adventure-works\ken0        |Chief Executive Officer                 |1969-01-29|S            |M     |2009-01-14|true        |           99|            69|true       |f01251e5-96a3-448d-981e-0f99d789110d|2014-06-30 00:00:00.000|/               |
               2|245797967       |adventure-works\terri0      |Vice President of Engineering           |1971-08-01|S            |F     |2008-01-31|true        |            1|            20|true       |45e8f437-670d-4409-93cb-f9424a40d6ee|2014-06-30 00:00:00.000|/1/             |
               3|509647174       |adventure-works\roberto0    |Engineering Manager                     |1974-11-12|M            |M     |2007-11-11|true        |            2|            21|true       |9bbbfb2c-efbb-4217-9ab7-f97689328841|2014-06-30 00:00:00.000|/1/1/           |
               4|112457891       |adventure-works\rob0        |Senior Tool Designer                    |1974-12-23|S            |M     |2007-12-05|false       |           48|            80|true       |59747955-87b8-443f-8ed4-f8ad3afdf3a9|2014-06-30 00:00:00.000|/1/1/1/         |
               5|695256908       |adventure-works\gail0       |Design Engineer                         |1952-09-27|M            |F     |2008-01-06|true        |            5|            22|true       |ec84ae09-f9b8-4a15-b4a9-6ccbab919b08|2014-06-30 00:00:00.000|/1/1/2/         |
               6|998320692       |adventure-works\jossef0     |Design Engineer                         |1959-03-11|M            |M     |2008-01-24|true        |            6|            23|true       |e39056f1-9cd5-478d-8945-14aca7fbdcdd|2014-06-30 00:00:00.000|/1/1/3/         |
               7|134969118       |adventure-works\dylan0      |Research and Development Manager        |1987-02-24|M            |M     |2009-02-08|true        |           61|            50|true       |4f46deca-ef01-41fd-9829-0adab368e431|2014-06-30 00:00:00.000|/1/1/4/         |
               8|811994146       |adventure-works\diane1      |Research and Development Engineer       |1986-06-05|S            |F     |2008-12-29|true        |           62|            51|true       |31112635-663b-4018-b4a2-a685c0bf48a4|2014-06-30 00:00:00.000|/1/1/4/1/       |
               9|658797903       |adventure-works\gigi0       |Research and Development Engineer       |1979-01-21|M            |F     |2009-01-16|true        |           63|            51|true       |50b6cdc6-7570-47ef-9570-48a64b5f2ecf|2014-06-30 00:00:00.000|/1/1/4/2/       |
              10|879342154       |adventure-works\michael6    |Research and Development Manager        |1984-11-30|M            |M     |2009-05-03|true        |           16|            64|true       |eaa43680-5571-40cb-ab1a-3bf68f04459e|2014-06-30 00:00:00.000|/1/1/4/3/       |
			  -- more --

Click to view Full table

Sample table: HumanResources.EmployeePayHistory

businessentityid|ratechangedate         |rate   |payfrequency|modifieddate           |
----------------+-----------------------+-------+------------+-----------------------+
               1|2009-01-14 00:00:00.000|  125.5|           2|2014-06-30 00:00:00.000|
               2|2008-01-31 00:00:00.000|63.4615|           2|2014-06-30 00:00:00.000|
               3|2007-11-11 00:00:00.000|43.2692|           2|2014-06-30 00:00:00.000|
               4|2007-12-05 00:00:00.000|   8.62|           2|2007-11-21 00:00:00.000|
               4|2010-05-31 00:00:00.000|  23.72|           2|2010-05-16 00:00:00.000|
               4|2011-12-15 00:00:00.000|29.8462|           2|2011-12-01 00:00:00.000|
               5|2008-01-06 00:00:00.000|32.6923|           2|2014-06-30 00:00:00.000|
               6|2008-01-24 00:00:00.000|32.6923|           2|2014-06-30 00:00:00.000|
               7|2009-02-08 00:00:00.000|50.4808|           2|2014-06-30 00:00:00.000|
               8|2008-12-29 00:00:00.000|40.8654|           2|2014-06-30 00:00:00.000|
			   -- more --

Click to view Full table

Sample Solution:

-- Selecting the JobTitle and maximum rate for each job title
SELECT 
    -- Selecting the JobTitle column
    JobTitle, 
    -- Calculating the maximum rate for each job title
    MAX(ph1.Rate) AS MaximumRate  
-- Selecting data from the Employee and EmployeePayHistory tables
FROM 
    HumanResources.Employee AS e  
    JOIN HumanResources.EmployeePayHistory AS ph1 ON e.BusinessEntityID = ph1.BusinessEntityID  
-- Grouping the results by JobTitle
GROUP BY 
    JobTitle  
-- Filtering the groups based on specific conditions
HAVING 
    (
        -- Checking if the maximum rate for male employees is greater than 40.00
        MAX(CASE WHEN Gender = 'M' THEN ph1.Rate ELSE NULL END) > 40.00  
        OR 
        -- Checking if the maximum rate for female employees is greater than 42.00
        MAX(CASE WHEN Gender = 'F' THEN ph1.Rate ELSE NULL END) > 42.00
    )  
-- Ordering the result set by MaximumRate in descending order
ORDER BY 
    MaximumRate DESC;

Explanation:

This SQL code retrieves data related to job titles and their corresponding maximum rates based on specific conditions.
The SELECT statement selects the JobTitle and calculates the maximum rate for each job title.
The tables Employee and EmployeePayHistory are joined based on the BusinessEntityID column.
The results are grouped by the JobTitle column.
The HAVING clause filters the groups based on specific conditions:

It checks if the maximum rate for male employees is greater than 40.00 OR if the maximum rate for female employees is greater than 42.00.

The ORDER BY clause arranges the result set in descending order based on the MaximumRate column.
This SQL query helps identify job titles where either the maximum rate for male employees exceeds 40.00 or the maximum rate for female employees exceeds 42.00, providing insights into salary disparities between genders for different job roles.

Sample Output:

jobtitle                        |maximumrate|
--------------------------------+-----------+
Chief Executive Officer         |      125.5|
Vice President of Production    |    84.1346|
Vice President of Sales         |    72.1154|
Vice President of Engineering   |    63.4615|
Chief Financial Officer         |    60.0962|
Research and Development Manager|    50.4808|
Information Services Manager    |    50.4808|
North American Sales Manager    |     48.101|
Pacific Sales Manager           |     48.101|
European Sales Manager          |     48.101|
Engineering Manager             |    43.2692|
Finance Manager                 |    43.2692|

SQL AdventureWorks Editor:

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