Scala set: Check if a given element exists in a set
Scala Set Exercise-6 with Solution
Write a Scala program to check if a given element exists in a set.
Sample Solution:
Scala Code:
object SetElementCheckExample {
def main(args: Array[String]): Unit = {
// Create a set
val nums = Set(1, 2, 3, 4)
// Print the set elements
println("Set: " + nums)
// Check if an element exists in the set
val element = 3
val exists = nums.contains(element)
// Print the result
if (exists) {
println(s"$element exists in the set.")
} else {
println(s"$element does not exist in the set.")
}
}
}
Sample Output:
Set: Set(1, 2, 3, 4) 3 exists in the set
Explanation:
In the above exercise,
- First, we create a set 'nums' containing the elements 1, 2, 3, and 4.
- To check if a given element exists in the set, we use the “contains()” method provided by the Set class. The "contains()" method takes an element as an argument and returns true if the set contains the element, and false otherwise.
- We store the result of the "contains()" method in the 'exists' variable.
- Finally, we use an if-else statement to print whether the given element exists in the set or not.
Scala Code Editor :
Previous: Check if a set is empty or not.
Next: Remove an element from a set.
What is the difficulty level of this exercise?
It will be nice if you may share this link in any developer community or anywhere else, from where other developers may find this content. Thanks.
https://w3resource.com/scala-exercises/sets/scala-set-exercise-6.php
- Weekly Trends and Language Statistics
- Weekly Trends and Language Statistics