Scala Program: Checking if a set is disjoint from another set

Last update on December 21 2024 10:24:54 (UTC/GMT +8 hours)

Write a Scala program to create a set and check if it is disjoint with another set.

Sample Solution:

Scala Code:

object DisjointCheckExample {
  def main(args: Array[String]): Unit = {
    // Create two sets
    val set1 = Set(1, 2, 3, 4)
    val set2 = Set(5, 6, 7)

    // Print the sets
    println("Set1: " + set1)
    println("Set2: " + set2)

    // Check if set1 is disjoint with set2
    val isDisjoint = set1.intersect(set2).isEmpty

    // Print the result
    if (isDisjoint) {
      println("Set1 is disjoint with Set2.")
    } else {
      println("Set1 is not disjoint with Set2.")
    }
  }
}

Sample Output:

Set1: Set(1, 2, 3, 4)
Set2: Set(5, 6, 7)
Set1 is disjoint with Set2.

Explanation:

In the above exercise,

• First, we create two sets set1 and set2 where set1 contains the elements 1, 2, 3, and 4, and set2 contains the elements 5, 6, and 7.
• To check if set1 is disjoint with set2, we use the intersect method to find common elements between the two sets. If the intersection is empty, the sets are disjoint.
• In the program, we check if set1 is disjoint with set2 by using the line val isDisjoint = set1.intersect(set2).isEmpty.
• Finally, we print the sets and the result of the disjoint check

Scala Code Editor :

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