Rust Function: Check even or odd

Last update on December 21 2024 10:20:11 (UTC/GMT +8 hours)

Write a Rust function that takes an integer and returns "even" if the integer is even and "odd" if it's odd.

Sample Solution:

Rust Code:

// Define a function named `even_or_odd` that takes an integer `num` as input and returns a static string slice.
fn even_or_odd(num: i32) -> &'static str {
    // Check if the remainder of `num` divided by 2 is equal to 0.
    if num % 2 == 0 {
        // If the remainder is 0, return "even".
        "even"
    } else {
        // If the remainder is not 0, return "odd".
        "odd"
    }
}

fn main() {
    // Print the result of calling `even_or_odd` function with 7 as input.
    println!("{}", even_or_odd(7)); // Output: odd
    // Print the result of calling `even_or_odd` function with 22 as input.
    println!("{}", even_or_odd(22)); // Output: even
}

Output:

odd
even

Explanation:

In the exercise above,

• The function "even_or_odd()" takes an integer 'num 'as input.
• Inside the function, it checks if the remainder of dividing 'num' by 2 is equal to 0. If it is, the function returns "even", indicating that the number is even.
• If the remainder is not equal to 0, the function returns "odd", indicating that the number is odd.
• In the "main()" function, examples of calling "even_or_odd()" are provided with different integers to demonstrate its usage.

Rust Code Editor:

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