Rust Program: Iterate over Option i32 values

Last update on December 21 2024 10:22:30 (UTC/GMT +8 hours)

Write a Rust program that iterates over a vector of Option values and prints the value of each Some variant.

Sample Solution:

Rust Code:

fn main() {
    let options = vec![Some(100), None, Some(200), None, Some(300)]; // Vector of Option values
    println!("Original options: {:?}", options); // Print the original vector

    // Iterate over the vector and print the value of each Some variant
    for option in options {
        if let Some(value) = option {
            println!("Value of Some variant: {}", value);
        }
    }
}

Output:

Original options: [Some(100), None, Some(200), None, Some(300)]
Value of Some variant: 100
Value of Some variant: 200
Value of Some variant: 300

Explanation:

In the exercise above,

• Define a vector 'options' containing 'Some' and 'None' variants of Option<i32> values.
• The original vector is printed using "println!()".
• We iterate over each element of the vector using a "for" loop.
• Inside the loop, we use pattern matching (if let) to check if the current element is 'Some' variant.
• If it is 'Some', we extract the value and print it using "println!()".

Rust Code Editor:

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