Rust Program: Swap Tuple elements

Last update on December 21 2024 10:20:05 (UTC/GMT +8 hours)

Write a Rust program that iterates over a vector of tuples (i32, i32) and swaps the elements of each tuple.

Sample Solution:

Rust Code:

fn main() {
    let tuples = vec![(10, 20), (30, 40), (50, 60)];

    // Iterate over each tuple, swap the elements, and collect into a new vector
    let swapped_tuples: Vec<(i32, i32)> = tuples
        .iter() // Use iter() instead of into_iter() to borrow the vector
        .map(|&(x, y)| (y, x)) // Swap the elements of each tuple
        .collect();

    println!("Original tuples: {:?}", tuples);
    println!("Swapped tuples: {:?}", swapped_tuples);
}

Output:

Original tuples: [(10, 20), (30, 40), (50, 60)]
Swapped tuples: [(20, 10), (40, 30), (60, 50)]

Explanation:

In the exercise above,

• let tuples = vec![(10, 20), (30, 40), (50, 60)];: Creates a vector 'tuples' containing tuples of integers.
• let swapped_tuples: Vec<(i32, i32)> = tuples.iter().map(|&(x, y)| (y, x)).collect();: Iterates over each tuple in 'tuples', swaps the elements of each tuple, and collects the results into a new vector 'swapped_tuples'. The "iter()" method is used to borrow the vector without consuming it. The "map()" method applies a closure to each tuple, swapping its elements. Finally, the "collect()" method collects the modified tuples into a new vector.
• println!("Original tuples: {:?}", tuples);: Prints the original vector of tuples.
• println!("Swapped tuples: {:?}", swapped_tuples);: Prints the vector of tuples with swapped elements.

Rust Code Editor:

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