Rust Vector Operations Guide

Last update on December 21 2024 10:19:31 (UTC/GMT +8 hours)

Write a Rust program to create a vector with integers 1 to 5. Then, append integers 6 to 10 to the vector. Finally, remove the last element from the vector and print the resulting vector.

Sample Solution:

Rust Code:

// Define the main function
fn main() {
    // Create a vector with integers 1 to 5
    let mut numbers: Vec<i32> = (1..=5).collect(); // Use the collect() method to create a vector from a range

    // Append integers 6 to 10 to the vector
    for i in 6..=10 {
        numbers.push(i); // Append the current value of i to the vector
    }

    // Remove the last element from the vector
    numbers.pop(); // Use the pop() method to remove the last element

    // Print the resulting vector
    println!("The resulting vector is: {:?}", numbers);
}

Output:

The resulting vector is: [1, 2, 3, 4, 5, 6, 7, 8, 9]

Explanation:

Here is a brief explanation of the above Rust code:

• fn main() {: This line defines the main function, which is the entry point of the program.
• let mut numbers: Vec<i32> = (1..=5).collect();: This line creates a mutable vector "numbers" containing integers from 1 to 5 using the "collect()" method with a range (1..=5).
• for i in 6..=10 {: This line starts a for loop that iterates from 6 to 10 (inclusive).
• numbers.push(i);: Inside the loop, each integer i from 6 to 10 is appended to the vector using the "push()" method.
• numbers.pop();: After appending integers 6 to 10, the "pop()" method is used to remove the last element from the vector.
• println!("The resulting vector is: {:?}", numbers);: Finally, the resulting vector is printed using the "println" macro with the {:?} format specifier to display the contents of the vector.

Rust Code Editor:

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