Rust Array update guide

Last update on December 21 2024 10:19:08 (UTC/GMT +8 hours)

Write a Rust program to create an array of characters with size 6 and initialize it with the characters 'A', 'B', 'C', 'D', 'E', and 'F'. Update the element at index 3 to 'P' and print the updated array.

Sample Solution:

Rust Code:

fn main() {
    // Define an array with a size of 6 and initialize it with characters
    let mut arr: [char; 6] = ['A', 'B', 'C', 'D', 'E', 'F']; // Declare an array of type char (character) with a size of 6 and initialize it with characters

    // Update the element at index 3 to 'P'
    arr[3] = 'P'; // Update the value at index 3 of the array to 'P'

    // Print the updated array
    println!("Updated Array: {:?}", arr); // Print the array using debug formatting
}

Output:

Updated Array: ['A', 'B', 'C', 'P', 'E', 'F']

Explanation:

Here is a brief explanation of the above Rust code:

• fn main() {: This line defines the main function, which is the entry point of the Rust program.
• let mut arr: [char; 6] = ['A', 'B', 'C', 'D', 'E', 'F'];: This line declares an array named 'arr' of type char (character) with a size of 6, and initializes it with the characters 'A', 'B', 'C', 'D', 'E', and 'F'.
• arr[3] = 'P';: This line updates the value at index 3 of the array 'arr' to 'P'. The value at index 3 is accessed using the indexing syntax 'arr[3]', and it is assigned the value 'P'.
• println!("Updated Array: {:?}", arr);: This line prints the updated array to the console. The {:?} syntax within the "println!" macro indicates that the array should be printed using its debug representation, which is suitable for printing arrays.

Rust Code Editor:

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