Rust Array initialization guide

Last update on December 21 2024 10:21:29 (UTC/GMT +8 hours)

Write a Rust program to create an array of integers with size 7 and initialize it with values 1, 2, 3, 4, 5, 6 and 7. Print the array.

Sample Solution:

Rust Code:

fn main() {
    // Define an array with a size of 7 and initialize it with the specified values
    let arr: [i32; 7] = [1, 2, 3, 4, 5, 6, 7]; // Declare an array of type i32 (integer) with a size of 7 and initialize it with values

    // Print the array
    println!("Array: {:?}", arr); // Print the array using debug formatting
}

Output:

Array: [1, 2, 3, 4, 5, 6, 7]

Explanation:

Here is a brief explanation of the above Rust code:

• fn main() {: This line defines the main function, which is the entry point of the Rust program.
• let arr: [i32; 7] = [1, 2, 3, 4, 5, 6, 7];: This line declares an array named 'arr' of type i32 (integer) with a size of 7, and initializes it with the specified values [1, 2, 3, 4, 5, 6, 7].
• println!("Array: {:?}", arr);: This line prints the array to the console. The {:?} syntax within the "println!" macro indicates that the array should be printed using its debug representation, which is suitable.

Rust Code Editor:

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