Rust Program: Variable counter operations

Last update on December 21 2024 10:20:55 (UTC/GMT +8 hours)

Write a Rust program that declares a mutable variable counter and initializes it with 0. Then increase it by 1 and decrease it by 1. At the end, print the variable value for each stage.

Sample Solution:

Rust Code:

fn main() {
    // Declare a mutable variable named 'counter' and initialize it with the value 0
    let mut counter = 0;

    // Print the initial value of the variable 'counter'
    println!("Initial value of counter: {}", counter);

    // Increase the value of 'counter' by 1
    counter += 1;

    // Print the value of 'counter' after increasing it
    println!("Value of counter after increasing: {}", counter);

    // Decrease the value of 'counter' by 1
    counter -= 1;

    // Print the value of 'counter' after decreasing it
    println!("Value of counter after decreasing: {}", counter);
}

Output:

Initial value of counter: 0
Value of counter after increasing: 1
Value of counter after decreasing: 0

Explanation:

Here's a brief explanation of the above Rust code:

• fn main() { ... }: This is the entry point of the program, where execution begins.
• let mut counter = 0;: This line declares a mutable variable named counter and initializes it with the value 0.
• println!("Initial value of counter: {}", counter);: This line prints the initial value of the variable counter using the println! macro. The {} is a placeholder for the value of counter, which is provided as an argument to the println! macro.
• counter += 1;: This line increases the value of the variable counter by 1.
• println!("Value of counter after increasing: {}", counter);: This line prints the value of the variable counter after increasing it.
• counter -= 1;: This line decreases the value of the variable counter by 1.
• println!("Value of counter after decreasing: {}", counter);: This line prints the value of the variable counter after decreasing it using the println! macro.

Rust Code Editor:

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