Check Perfect number using While loop in R
R Programming: Control Structure Exercise-15 with Solution
Write a R program function to check if a given number is a perfect number using a while loop.
From Wikipedia -
In number theory, a perfect number is a positive integer that is equal to the sum of its positive divisors, excluding the number itself. For instance, 6 has divisors 1, 2 and 3 (excluding itself), and 1 + 2 + 3 = 6, so 6 is a perfect number. The next perfect number is 28, since 1 + 2 + 4 + 7 + 14 = 28.
Sample Solution :
R Programming Code :
# Define a function to check if a given number is a perfect number using a while loop
is_perfect_number <- function(number) {
# Initialize variables
sum_of_divisors <- 0
divisor <- 1
# Find proper divisors and sum them
while (divisor < number) {
if (number %% divisor == 0) {
sum_of_divisors <- sum_of_divisors + divisor
}
divisor <- divisor + 1
}
# Check if the number is a perfect number
if (sum_of_divisors == number) {
return(TRUE) # Number is a perfect number
} else {
return(FALSE) # Number is not a perfect number
}
}
# Test the function with an example input
number <- 28 # Example number to check if it's a perfect number
is_perfect <- is_perfect_number(number)
# Print the result
if (is_perfect) {
cat(number, "is a perfect number.\n")
} else {
cat(number, "is not a perfect number.\n")
}
Output:
28 is a perfect number.
Explatnaion:
In the exercise above,
- The "is_perfect_number()" function takes a positive integer 'number' as input and checks if it's a "perfect" number.
- It initializes 'sum_of_divisors' to 0 and 'divisor' to 1.
- It iterates through each divisor less than 'number' using a while loop.
- For each divisor that evenly divides 'number', it adds it to 'sum_of_divisors'.
- After finding all the proper divisors and summing them, it checks if 'sum_of_divisors' is equal to 'number'.
- If they are equal, the function returns 'TRUE', indicating that the number is a "perfect" number. Otherwise, it returns 'FALSE'.
R Programming Code Editor:
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