Python Tkinter: Opening a file dialog for file selection
Write a Python program that opens a file dialog to allow the user to select a file for processing using Tkinter.
Sample Solution:
Python Code:
Explanation:
In the exercise above -
- Import tkinter as tk and filedialog for creating the GUI components and opening the file dialog.
- Define the open_file_dialog() function, which opens the file dialog using filedialog.askopenfilename(). This dialog allows the user to select a file with specified file types. If a file is selected, it updates a label with the selected file path and calls the "process_file()" function.
- Define the "process_file()" function as a placeholder for your file processing logic. In this example, it reads the contents of the selected file and displays them in a "Text" widget.
- Create the main Tkinter window, set its title, and create the "Open File" button, which calls the open_file_dialog() function when clicked.
- Create a label to display the selected file path.
- Create a "Text" widget to display the contents of the selected file.
- The main event loop, root.mainloop(), starts the Tkinter application.
Sample Output:
Flowchart:

Python Code Editor:
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