Python: Count characters at same position in a given string as in English alphabet

Last update on March 21 2025 12:53:50 (UTC/GMT +8 hours)

Count chars matching English alphabet position.

Write a Python program to count characters at the same position in a given string (lower and uppercase characters) as in the English alphabet.

Visual Presentation:

Sample Solution:

Python Code:

# Function to count characters at same position
def count_char_position(str1):

  count_chars = 0

  # Iterate through string
  for i in range(len(str1)):

    # Check if position matches ASCII value
    if ((i == ord(str1[i]) - ord('A')) or 
        (i == ord(str1[i]) - ord('a'))):
      
      count_chars += 1

  return count_chars

# Get input string  
str1 = input("Input a string: ")

# Print result
print("Number of characters of the said string at same position as in English alphabet:")
print(count_char_position(str1)) 

Sample Output:

Input a string:  xbcefg
Number of characters of the said string at same position as in English alphabet:
2

Flowchart:

For more Practice: Solve these Related Problems:

• Write a Python program to count how many characters in a string are in the same position as they appear in the English alphabet.
• Write a Python program to iterate through a string and compare each letter’s index with its position in the alphabet to count matches.
• Write a Python program to implement a function that returns the count of characters whose order in the alphabet equals their index in the string.
• Write a Python program to use ord() and list comprehension to check if each character's position in a string corresponds to its alphabetical order.

Python Code Editor:

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