Python: Update all the values of a specific column of a given SQLite table

Last update on April 02 2025 12:40:41 (UTC/GMT +8 hours)

10. Update All Column Values

Write a Python program to update all the values of a specific column of a given SQLite table.

Sample Solution:

Python Code :

import sqlite3 
from sqlite3 import Error 
def sql_connection():
    try:
      conn = sqlite3.connect('mydatabase.db')
      return conn
    except Error:
      print(Error) 
def sql_table(conn):
    cursorObj = conn.cursor()
# Create the table
    cursorObj.execute("CREATE TABLE salesman(salesman_id n(5), name char(30), city char(35), commission decimal(7,2));")
# Insert records
    cursorObj.executescript("""
    INSERT INTO salesman VALUES(5001,'James Hoog', 'New York', 0.15);
    INSERT INTO salesman VALUES(5002,'Nail Knite', 'Paris', 0.25);
    INSERT INTO salesman VALUES(5003,'Pit Alex', 'London', 0.15);
    INSERT INTO salesman VALUES(5004,'Mc Lyon', 'Paris', 0.35);
    INSERT INTO salesman VALUES(5005,'Paul Adam', 'Rome', 0.45);
    """)    
    cursorObj.execute("SELECT * FROM salesman")
    rows = cursorObj.fetchall()
    print("Agent details:")
    for row in rows:
        print(row)
    print("\nUpdate all commision to .55:")
    sql_update_query = """Update salesman set commission = .55"""
    cursorObj.execute(sql_update_query)
    conn.commit()
    print("Record Updated successfully ")    
    cursorObj.execute("SELECT * FROM salesman")
    rows = cursorObj.fetchall()
    print("\nAfter updating Agent details:")
    for row in rows:
        print(row)
sqllite_conn = sql_connection()
sql_table(sqllite_conn)
if (sqllite_conn):
  sqllite_conn.close()
  print("\nThe SQLite connection is closed.")

Sample Output:

Agent details:
(5001, 'James Hoog', 'New York', 0.15)
(5002, 'Nail Knite', 'Paris', 0.25)
(5003, 'Pit Alex', 'London', 0.15)
(5004, 'Mc Lyon', 'Paris', 0.35)
(5005, 'Paul Adam', 'Rome', 0.45)

Update all commision to .55:
Record Updated successfully 

After updating Agent details:
(5001, 'James Hoog', 'New York', 0.55)
(5002, 'Nail Knite', 'Paris', 0.55)
(5003, 'Pit Alex', 'London', 0.55)
(5004, 'Mc Lyon', 'Paris', 0.55)
(5005, 'Paul Adam', 'Rome', 0.55)

The SQLite connection is closed.

For more Practice: Solve these Related Problems:

• Write a Python program to update all values of a specific column in a SQLite table to a new constant value, then print the table contents.
• Write a Python function that takes a table name and column name, updates every row with a computed value (e.g., incrementing by 10), and prints the result.
• Write a Python script to change the status column for all rows in a table to 'active' and then display the updated rows.
• Write a Python program to update all entries in a numerical column by applying a mathematical operation (e.g., multiplication by 2) and verify the update with a SELECT query.

Python Code Editor:

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