Python: Raise Timeout exception in the event of times out of request

Last update on April 02 2025 12:37:53 (UTC/GMT +8 hours)

6. Async Request Timeout

Write a Python program to send a request to a web page and stop waiting for a response after a given number of seconds. If a request times out, raise a Timeout exception.

Sample Solution:

Python Code:

import requests
print("timeout = 0.001")
try:
    r = requests.get('https://github.com/', timeout = 0.001)
    print(r.text)
except requests.exceptions.RequestException as e:
    print(e)    

print("\ntimeout = 1.0")    
try:
    r = requests.get('https://github.com/', timeout = 1.0)
    print("Connected....!")
except requests.exceptions.RequestException as e:
    print(e)

Sample Output:

timeout = 0.001
HTTPSConnectionPool(host='github.com', port=443): Max retries exceeded with url: / (Caused by ConnectTimeoutError(<urllib3.connection.VerifiedHTTPSConnection object at 0x0BD7B0D0>, 'Connection to github.com timed out. (connect timeout=0.001)'))

timeout = 1.0
Connected....!

For more Practice: Solve these Related Problems:

• Write a Python program that sends a request to a URL with a specified timeout using requests.get(timeout=...), and prints a message if the request times out.
• Write a Python function that attempts to fetch data from a slow server, catches the Timeout exception, and then logs an error message.
• Write a Python script to simulate a timeout scenario by sending a request with a very short timeout period, then printing the exception details if a timeout occurs.
• Write a Python program to prompt the user for a timeout duration, send a request with that timeout, and handle both successful and timeout responses appropriately.

Python Code Editor:

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