Python: Matches a word at the end of a string, with optional punctuation

Last update on December 31 2024 07:12:09 (UTC/GMT +8 hours)

Write a Python program that matches a word at the end of a string, with optional punctuation.

Sample Solution:

Python Code:

import re
def text_match(text):
        patterns = '\w+\S*$'
        if re.search(patterns,  text):
                return 'Found a match!'
        else:
                return('Not matched!')

print(text_match("The quick brown fox jumps over the lazy dog."))
print(text_match("The quick brown fox jumps over the lazy dog. "))
print(text_match("The quick brown fox jumps over the lazy dog "))

Sample Output:

Found a match!                                                                                                
Not matched!                                                                                                  
Not matched!

Pictorial Presentation:

Flowchart:

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program that matches a word at the beginning of a string.
Next: Write a Python program that matches a word containing 'z'.