Python: Calculate the average of the numbers a through b rounded to nearest integer, in binary

Python Programming Puzzles: Exercise-81 with Solution

Write a Python program to calculate the average of the numbers a through b (b not included) rounded to the nearest integer, in binary (or -1 if there are no such numbers).

Input: 
4 , 7
Output:
0b101

Input:  
11 , 19
Output:
0b1110

Visual Presentation:

Sample Solution:

Python Code:

# License: https://bit.ly/3oLErEI

# Define a function named 'test' that takes two integer parameters, 'a' and 'b'
def test(a, b):
    # Create a range of integers from 'a' to 'b' (exclusive)
    r = range(a, b)
    
    # Check if the range is empty
    if len(r) == 0:
        return "-1"  # Return "-1" if the range is empty
    
    # Calculate the average of the numbers in the range, round to the nearest integer,
    # and convert the result to binary representation
    return bin(round(sum(r) / len(r)))

# Example 1
a1 = 4
b1 = 7
print("Range:", a1, ",", b1)
print("Average of the numbers", a1, "through", b1, "rounded to the nearest integer, in binary:")
print(test(a1, b1))

# Example 2
a2 = 11
b2 = 19
print("\nRange:", a2, ",", b2)
print("Average of the numbers", a2, "through", b2, "rounded to the nearest integer, in binary:")
print(test(a2, b2))

Sample Output:

Range: 4 , 7
Average of the numbers 4 through 7 rounded to nearest integer, in binary:
0b101

Range: 11 , 19
Average of the numbers 11 through 19 rounded to nearest integer, in binary:
0b1110

Flowchart:

Python Code Editor :

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Round each float in a list of numbers up to the next integer and return the running total of the integer squares.
Next: Find the sublist of numbers with only odd digits in increasing order.